Answer:
Step-by-step explanation:
Let the number of dimes be d and quarters be q
<u>The value is $8.80 = 880¢, so:</u>
- 10d + 25q = 880 ⇒ 2d + 5q = 176
<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>
- 25d + 10q = 730 ⇒ 5d + 2q = 146
<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>
- 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
- 4d - 25d = -378
- -21d = -378
- d = -378/-21
- d = 18
A parallel set of lines are two lines that do not touch one another, but are on the same plane and are equidistant forever. Think about two highways that run next to each other but never touch or cross. CF, therefore, could be parallel to BE, AH, and DG.
Answer:
Question #1: Option C, (x - 1)(x^2 + x + 1)(x + 1)(x^2 - x + 1)
Question #2: Option C, 8x^3−56x^2+12x−84
Step-by-step explanation:
Question #1
<u>Step 1: Factor</u>
p(x) = x^6 - 1
<em>p(x) = (x + 1)(x - 1)(x^2 + x + 1)(x^2 - x + 1)</em>
<em />
Answer: Option C, (x - 1)(x^2 + x + 1)(x + 1)(x^2 - x + 1)
Question #2
<u>Step 1: Expand</u>
p(x) = 4(x - 7)(2x^2 + 3)
p(x) = (4x - 28)(2x^2 + 3)
p(x) = 8x^3 + 12x - 56x^2 - 84
<em>p(x) = 8x^3 - 56x^2 + 12x - 84</em>
<em />
Answer: Option C, 8x^3−56x^2+12x−84
$1.33 for each lemon because 8/6=1.33333 and so on so the answer would be $1.33
