All categories

3 years ago

The radius of circular pond is 35m.Calculate the area of the path 3.5m wide running outside the pond.

Mathematics

1 answer:

olganol [36]3 years ago

3 0

Answer:

3848,451001

Step-by-step explanation:

A = πr²

A = π[35]²

A = 1225π

A = 3848,451001

I hope this is correct, and as always, I am joyous to assist anyone at any time.

You might be interested in

Michael is putting 12 boxes in a storage shed. Each box is in the shape of a rectangular prism with dimensions 1.5 feet by 1.5 f

pishuonlain [190]

Answer:

Volume of room will be left after Michael stores the boxes 426 feet cube

Step-by-step explanation:

It is given that

Michael is putting 12 boxes in a storage shed.

Each box is in the shape of a rectangular prism with dimensions 1.5 feet by 1.5 feet by 2 feet.

If the storage shed has dimensions 6 feet by 10 feet by 8 feet,

To find the volume of one box

Volume = 1.5 x 1.5 x 2= 4.5 feet cube

Volume of 12 such box = 4.5 x 12 =54 feet cube

To find the volume of shed

Volume of Shed = 6 x 10 x 8 =480

To find remaining portion of shed

Volume of room will be left after Michael stores the boxes =volume of shed - volume of box

=480 - 54 = 426 feet cube

7 0

3 years ago

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

3 years ago

In the diagram below, is an altitude of DEF. What is the length of ? If necessary, round your answer to two decimal places.

padilas [110]

I hope this helps you

5 0

3 years ago

Find the value of X (Gotta choose at least 2) x = 52 x = 2 x = 3 x = 33

Ad libitum [116K]

Answer:

Before this problem gets an answer, can you define "gotta." Does this work mean isosceles?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given

Soloha48 [4]

Answer:

what? I don't get it?

Step-by-step explanation:

4 0

3 years ago

The radius of circular pond is 35m.Calculate the area of the path 3.5m wide running outside the pond. ​

The radius of circular pond is 35m.Calculate the area of the path 3.5m wide running outside the pond.