Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test
Formula : 
Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
his mistake was that he didnt follow the rules of the order of operations and he multiplied 4 by 4 and just added the third power and the 6th power getting the wrong answer
hope this helps:) good luck
Answer:
Step-by-step explanation:
Slope-intercept form means
where m is given its the slope which is 
and we have the coordinates x and y which is (4, -5) and we need to find the value of c which is the y-intercept so we insert all these values into the equation so ,
now we know the value of slope which is given and we found the value of which is 1 so we put these values into our original slope-intercept form equation
Answer with explanation:
Given : The computed r -value = 0.45
Sample size : n=18
Degree of freedom : 
Now, the critical value for Pearson correlation coefficient for a two-tailed test at a .05 level of significance will be :
( by critical correlation coefficient table)
Since , 
i.e. 0.45>0.468 , then we say that his Pearson correlation coefficient is not significant for a two-tailed test at a .05 level of significance.
