Answer:
Attached diagram A'B'C'D'
Step-by-step explanation:
Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.
We see that scale factor is less than 1 which means it shrinks the image to a smaller one.
To draw a scaled copy, we need to find the lengths of its sides.
To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.
Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.
So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.
A^2 + b^2 = c^2.....a and b are the legs and c is the hypotenuse
4^2 + b^2 = 5^2
16 + b^2 = 25
b^2 = 25 - 16
b^2 = 9
b = sq rt 9
b = 3 m
1 meter = 100 cm....so 3 meters = 3(100) = 300 cm
ur answer : the tree is 300 cm high
★ CONJECTURE ★
Statement - The cube of an even number is an even number .
Obviously 2nd option will satisfy the same ,
if you've mentioned the exact equation
aslike it's
Cubing is multiplication factor 3 times of the number , 2 is an even number and it's cube 8 is also an even number , Hence proved
415 + d ≥ 500
Because they want a minumin of 500 so that means there could be more than 500 like 700
HOPE THIS HELPS!