3 years ago

Find the value of n such that x2-10x+n is a perfect square trinomial.

2 answers:

mihalych1998 [28]3 years ago

7 0

The answer is the last option (Option D), which is:

D. 25

The explanation is shown below:

1. You have that:

(a ± b)^2=a^2 ± 2ab + b^2

2. The expression given in the problem is:

x^2-10x+n

Where x^2=a and 2ab=10x

2b=10
b=10/2
b=5

3. Therefore, you have:

b^2=5
b^2=25

b^2=n
n=25

sleet_krkn [62]3 years ago

3 0

Answer:

the answer is 25!!

Step-by-step explanation:

I hope this is helpful to sum of y'all!!

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