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nexus9112 [7]
3 years ago
8

Find the value of n such that x2-10x+n is a perfect square trinomial.

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0
The answer is the last option (Option D), which is:

 D. 25

 The explanation is shown below:

 1. You have that:

 (a ± b)^2=a^2 <span>± 2ab + b^2

 2. The expression given in the problem is:

 </span><span>x^2-10x+n

 Where x^2=a and 2ab=10x

 2b=10
 b=10/2
 b=5

 3. Therefore, you have:

 b^2=5
 b^2=25

 b^2=n
 n=25</span>
sleet_krkn [62]3 years ago
3 0

Answer:

the answer is 25!!

Step-by-step explanation:

I hope this is helpful to sum of y'all!!

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<h3>Perimeter and area of the triangle giving the equation of a line</h3>

First we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

From the given equation of the lines, the points of intersection of the line are (x₁, y₁) = (- 0.4, 5.2), (x₂, y₂) = (-0.8, 4.4) and (x₃, y₃) = (0, 4)

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For the height

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<u>For the area</u>

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A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/21511715

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