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3 years ago

Find the value of n such that x2-10x+n is a perfect square trinomial.

2 answers:

mihalych1998 [28]3 years ago

7 0

The answer is the last option (Option D), which is:

D. 25

The explanation is shown below:

1. You have that:

(a ± b)^2=a^2 ± 2ab + b^2

2. The expression given in the problem is:

x^2-10x+n

Where x^2=a and 2ab=10x

2b=10
b=10/2
b=5

3. Therefore, you have:

b^2=5
b^2=25

b^2=n
n=25

sleet_krkn [62]3 years ago

3 0

Answer:

the answer is 25!!

Step-by-step explanation:

I hope this is helpful to sum of y'all!!

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3x+2y=4 8x+5y=9 Please solve using Cross multiplication method.

ch4aika [34]

Hello, Please refer the photo attachment for your question's answer. The final answer is :-

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Answered by Benjemin

3 0

3 years ago

Ted and Jude are each saving money each month. After x months, the amount of money, in dollars, that Ted has saved is represente

Nadusha1986 [10]

Answer:

True Statements are -

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

Step-by-step explanation:

Given - Ted and Jude are each saving money each month. After x months, the amount of money, in dollars, that Ted has saved is represented by the

equation T = 40x, and the amount of money that Jude has saved is represented by the equation J = 60x.

To find - Choose all of the statements that are true.

A. Each month, Jude saves two-thirds as much money as Ted saves.

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

C. The amount of money Jude saves each month is $20 more than the amount Ted saves each month.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

Proof -

Given that,

After x months,

Ted saved the amount of money, T(x) = 40x

Jude saved the amount of money, J(x) = 60x

Now,

In 1 month,

Ted saved money, T(1) = 40(1) = 40

Jude saved money, J(1) = 60(1) = 60

So,

In 1st month, Jude saved money 20 more than Ted saved.

Now,

In 2 month,

Ted saved money, T(2) = 40(2) = 80

Jude saved money, J(2) = 60(2) = 120

So,

In 2nd month, Jude saved money 40 more than Ted saved.

Now,

In 3 month,

Ted saved money, T(3) = 40(3) = 120

Jude saved money, J(3) = 60(3) = 180

So,

In 3rd month, Jude saved money 60 more than Ted saved.

So,

Option C is incorrect

Because

In 1st month, Jude saves is $20 more than the amount Ted saves

In 2nd month, Jude saves is $40 more than the amount Ted saves

Now,

In 1st month,

Ted saves = 40

and

$\frac{2}{3}(40)$ = 26.67

So, Jude will save = 40 + 26.67 = 66.67

But Jude saves 60

So,

Option A is incorrect.

i.e. A. Each month, Jude saves two-thirds as much money as Ted saves.

Now,

We can see that,

In 3 months, Ted will have saved the money = 120

In 2 months, Jude will have saved the money = 120

So,

Option B is correct.

i.e. B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

Also,

We can see that

In 1st month, Jude saved money 20 more than Ted saved.

In 2nd month, Jude saved money 40 more than Ted saved.

In 3rd month, Jude saved money 60 more than Ted saved.

So,

Option D is correct.

i.e. D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

∴ we get

True Statements are -

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

7 0

2 years ago

What is the radius of circle with the equation (x - 2)^2 + (y - 1)^2 = 9 * 18 9 81 3

Free_Kalibri [48]

Answer:

Step-by-step explanation:

5 0

3 years ago

THE QUESTION IS IN THE PICTURE CAN SOMEONE PLLLLSSLSLS HELP

Genrish500 [490]

Answer:

I HELPED :D

Step-by-step explanation:

3 0

3 years ago

Let ∠Q be an acute angle such that tanQ=0.04. Use a calculator to approximate the measure of ∠Q to the nearest tenth of a degree

Digiron [165]

We have been given that ∠Q is an acute angle such that $\text{tan}(Q)=0.04$ . We are asked to find the measure of angle Q to nearest tenth of a degree.

We will use arctan to solve for measure of angle Q as:

$Q=\text{tan}^{-1}(0.04)$

Now we will use calculator to solve for Q as:

$Q=2.290610042639^{\circ}$

Upon rounding to nearest tenth of degree, we will get:

$Q=2.3^{\circ}$

Therefore, measure of angle Q is approximately 2.3 degrees.

7 0

2 years ago