The lowest common denominator for 15 and 12 will get in this way
15=3*5
12 = 3*4
LCM will be 3*4*5=12*5=60
We want to see how many solutions has an equation given some restrictions on the vectors of the equation.
We have 3 vectors in R2.
v₁, v₂, and v₃.
Where we know that v₁ and v₂ are parallel. And two vectors are parallel if one is a scalar times the other.
Then we can write:
v₂ = c*v₁
Where c is a real number.
Then our system:
x*v₁ + y*v₂ = v₃
Can be rewriten to:
x*v₁ + y*c*v₁ = v₃
(x + y*c)*v₁ = v₃
Assuming x, y, and c are real numbers, this only has a solution if v₁ is also parallel to v₃, because as you can see, the equation says that v₃ is a scallar times v₁.
Geometrically, this means that if we sum two parallel vectors, we will get a vector that is parallel to the two that we added.
If you want to learn more, you can read:
brainly.com/question/13322477
Answer:
-3yc+3y2+8c-8y
Step-by-step explanation:
(3y-8)(-c+y)
3y(-c+y)-8(-c+y)
-3yc+3y2+8c-8y
Answer:
o (x-1)(x2-x+1)
Step-by-step explanation:
i think hopefully it's right
Answer:
The 3, and -4 are the places where you start, then just graph 1/2 and -3 as slope
Step-by-step explanation: