Suppose a 95% confidence interval for the average amount of weight loss on a diet program for males is between 13.0 and 18.0 pou
1 answer:
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here,
2x-6y= -12
2(x-3y)= -12
x-3y = -6...........eq1
x+2y=14............eq2
we can subtract the above two given equations
we get,
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so,
y=4
now to find the value of x we have to substitute the value of y in any of the above two equations, I choose eq2
we get,
Answer:
the answer is in the link
Step-by-step explanation:
9514 1404 393
Answer:
WX = 33
(x, y) = (2, 10)
Step-by-step explanation:
The hash marks tell you WX is a midline, so has the measure of the average of the two bases.
WX = (PQ +SR)/2 = (27 +39)/2 = 66/2
WX = 33
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The hash marks also tell you ...
PW = WS
y +4x = 18 . . . . . . substitute the given expressions
and also
QX = XR
2y +x = 22 . . . . . substitute the given expressions
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If you solve the first equation for y, you get ...
y = 18 -4x
Substituting that into the second equation gives ...
2(18-4x) +x = 22
36 -7x = 22 . . . . . . . simplify
14 = 7x . . . . . . . . . . . add 7x-22 to both sides
2 = x . . . . . . . . . . . . divide by 7
y = 18 -4(2) = 10 . . . find y using the above relation
The values of x and y are 2 and 10, respectively.
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My favorite "quick and dirty" way to solve a set of linear equations is using a graphing calculator. It works well for integer solutions.
First let us convert 0.01 into fraction:
Now we convert 100 and 4 into perfect squares as follows:
Now we use the property of :