Given that a parking lot contains 100 cars, k of which happen to be lemons.
This is a conditional probability question.
Let event A be that a car is tested and event B be that a car is lemon.
The probability that a car is lemon is given by

The probability that a car is tested is given by

The probability that a car is lemon and it is tested is given by

For a conditional probability, the probablility of event A given event B is given by:

Therefore, the probability that a car is lemon, given that it is tested is given by.
Answer:
4.5=4 and 1/2
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Find the following limit:
lim_(x->∞) 3^(-x) n
Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):
n/(lim_(x->∞) 3^x)
Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):
n/3^(lim_(x->∞) x)
lim_(x->∞) x = ∞:
n/3^∞
n/3^∞ = 0:
Answer: 0
Answer:
a. 12/37
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Sin = Opposite/Hypotenuse
sin(A) = BC/AB = 12/37