Answer:
step 1: mRNA attaches to the ribosome
step 2: tRNA's attach to free amino acids in the cytoplasmic "pool" of amino acids
step 3: tRNA carries its specific amino acid to the ribosome
step 4: tRNA "delivers" its amino acid based on complementary pairing of a triplet code (anticodon) with the triplet code (codon) of the mRNA
step 5: Enzyme "hooks" the amino acid to the last one in the chain forming a peptide bond
step 6: Protein chain continues to grow as each tRNA brings in its amino acid and adds it to the chain
Answer:
Thermosensitive liposomes (TSL) are promising tools used to deliver drugs to targeted region when local hyperthermia is applied (∼40–42°C) which triggers the membrane phase transformation from a solid gel-like state to a highly permeable liquid state. Selective lipid components have been used to in TSL formulations to increase plasma stability before hyperthermia and speed drug release rate after. Two generations of TSL technology have been developed. The traditional thermal sensitive liposomes (TTSL) have utilized DPPC and DSPC as a combination. The second generation, lysolipid thermally sensitive liposomes (LTSL) technology, has been developed with incorporation of lysolipids that form stabilized defects at phase transition temperature. LTSL maintains certain favorable attributes:
High percentage of lysolipids incorporation;
Minimum leakage for therapeutical drugs encapsulation;
Ultrafast drug release upon heating (3.5 times enhanced compared to TTSL). For example, ThermoDox, a commonly used LTSL drug for cancer, has been reported to release 100% of the encapsulated doxorubicin within 30s;
First and most successful formulation for intravascular drug release.
Explanation:
https://www.creative-biostructure.com/Lysolipid-Thermally-Sensitive-Liposomes-Production-612.htm
Answer:
(i) 1 moles of C
(ii) 4.5 moles of C
Explanation:
The Chemical equation is as follow,
A + 2 B → C
This chemical equation can be translated as;
(i) 1 mole of A reacts with 2 moles of B
(ii) 1 mole of A produces 1 mole of C
(iii) 2 moles of B reacts with 1 mole of A
(iv) 2 moles of B produces 1 mole of C
(v) 1 mole of C is produced by 1 mole of A and 2 moles of B
Therefore to find the number of moles of C produced by 2 mole of B we will do following proportional method.
As,
2 moles of B produced = 1 mole of C
So,
2 moles of B will produce = X moles of C
Solving for X,
X = 2 moles × 1 mole / 2 moles
X = 1 moles of C
Note:
In above problem the given moles were the same as that present in balance equation so incase if the moles are different from that of the equation then the method shown above can be used to solve it.
Lets try it for 9 moles of B:
As,
2 moles of B produced = 1 mole of C
So,
9 moles of B will produce = X moles of C
Solving for X,
X = 9 moles × 1 mole / 2 moles
X = 4.5 moles of C
Answer:
D
Explanation:
The heat will make water evaporate at a higher rate thus causing more rain
