What the contact between photosynthesis and respiration

In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant

Ivenika [448]

Answer and Explanation:

Available data:

Comb shape is determined by genes at two loci (R, r and P, p).

The walnut comb genotype is R_P_.

The rose comb genotype is R_pp.

The pea comb genotype is rrP_.

The single genotype is rrpp.

a. Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring:

Parental) RrPp x rrpp

Gametes) RP Rp rP rp rp rp rp rp

Punnet Square) RP Rp rP rp

rp RrPp Rrpp rrPp rrpp

rp RrPp Rrpp rrPp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. Rose crossed with pea produces 20 walnut offspring.

Parental) RRpp x rrPP

Gametes) Rp Rp Rp Rp rP rP rP rP

Punnet Square) Rp Rp Rp Rp

rP RrPp RrPp RrPp RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. Pea crossed with single produces 1 single offspring.

This is not possible, because the pea genotype involves at least one dominant allele P. There are two possible crosses: rrPp x rrpp, which must produce half of the progeny pea and the other half single, or rrPP x rrpp which produce a whole pea progeny with no single offspring.

Parental) rrPp x rrpp

Gametes) rP rp rP rp rp rp rp rp

Punnet Square) rP rp rP rp

rp rrPp rrpp rrPp rrpp

rp rrPp rrpp rrPp rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring.

This is not possible, because having one of the parents with a rose phenotype involves at least one R allele, which means that there must be rose phenotype in the progeny.

Parental) Rrpp x rrPp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rP RrPp RrPp rrPp rrPp

rP RrPp RrPp rrPp rrPp

rp Rrpp Rrpp rrpp rrpp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. Rose crossed with single produces 31 rose offspring.

Parental) RRpp x rrpp

Gametes) Rp Rp Rp Rp rp rp rp rp

Punnet Square) Rp Rp Rp Rp

rp Rrpp Rrpp Rrpp Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. Rose crossed with single produces 10 rose and 11 single offspring.

Parental) Rrpp x rrpp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0

3 years ago

PLEASE HELP ITS TIMED

user100 [1]

Answer:

true

Explanation:

3 0

3 years ago

Read 2 more answers

Two planets with the same mass and atmospheric conditions orbit a single star. Planet A is closer to the star than Planet B. Whi

sveticcg [70]

Answer:

Planet B is expected to be cooler than Planet A.

Explanation:

In the given case, planet A is closer to the star than planet B. Their atmospheric conditions and mass is same so their surface temperature will depend on their distance from the star. Since planet A is closer, it will receive more radiation from the star. In turn it will be hotter to re-radiate that energy back to space. Hence, average surface temperature of planet B will be lower than planet A.

6 0

3 years ago

The process by which cells are drawn or attracted to an area by a microbe invader is known as ________.

Alexxx [7]

Answer:

chemotaxis

Explanation:

Chemotaxis is movement of the organism in the response to the chemical stimulus.

Bacteria, somatic cells and single-cell as well as multicellular organisms direct movements of their body according to some chemicals in the environment. This is very important for the bacteria to find the food by swimming toward highest concentration of the food molecules or also to flee from the poisons.

Thus, it is a process by which various cells are drawn to the target area by a microbe invader.

7 0

3 years ago

Gloria is experiencing pain in the upper right portion of her abdomen, has greasy diarrhea, and bleeds excessively when she mens

Volgvan

Bile

Based on the above symptoms, it can be inferred that Gloria lacks bile. Pain in the upper right portion of the abdomen usually corresponds to problems with the liver. The liver produces bile (also known as gall), which is a dark green to yellowish brown fluid that helps most vertebrates with digestion. It increases the absorption of fats and fat-soluble substances such as vitamins A,D,E, and K. It is also necessary for the excretion of bilirubin, which is a byproduct when red blood cells are recycled by the liver.

Bile deficiency can cause the fats in the food to be undigested and these fats end up excreted as part of feces. It can also lead to vitamin deficiency and a gradual build-up of toxins in the liver.

5 0

3 years ago