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3 years ago

PLEASE HELP WILL GIVE BRANLIEST pythagorean theorem

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

Answer:

It is easy...

replace the value...

like 1st. ..

$3^{2} + 4^{2} = {5}^{2} \\ or \: 9 + 16 = 25 \\or \: 25 = 25 \\ proved$

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Can somebody help me with this problem . 3.)find the perimeter of the object below.

AysviL [449]

Answer:

189

Step-by-step explanation:

Multiple 15 by 13 and get 195

Multiply 3 by 2 and get 6

Subtract 195 by 6 and get 189

Hope it helps

7 0

3 years ago

Read 2 more answers

Please help!!

Rama09 [41]

The associative property of addition is pretty much just any numbers in place of these: a + (b + c) = (a + b) + c. Therefore, your answer would be d) (6 + 1) + 9 = 6 + (1 + 9)

6 0

3 years ago

Write 169=13^2 in logarithmic form

e-lub [12.9K]

Answer:

$\log_{13}(169)=2$

Step-by-step explanation:

The given exponential form is:

$169=13^2$

The base of the given expression on the right is 13 and the exponent is 2.

The number is 169.

In terms of logarithms, the base still remains the base and the exponent becomes the result of the logarithm of the number 169 to the given base 13.

$\log_{13}(169)=2$

4 0

3 years ago

Find the domain of the graphed function. (Please help me)

mel-nik [20]

Answer:

Step-by-step explanation:

I belive it is a .

8 0

3 years ago

Refer to the previous exercise. The researchers wanted a sufficiently large sample to be able to estimate the probability of pre

Maru [420]

Answer:

The large sample n = 117.07

Step-by-step explanation:

Step(i):-

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

Step(ii):-

The Marginal error is determined by

M.E = $\frac{Z_{0.05} \sqrt{p(1-p)} }{\sqrt{n} }$

$0.08 = \frac{2 X \sqrt{0.75(1-0.75)} }{\sqrt{n} }$

Cross multiplication , we get

$\sqrt{n} = \frac{2 X \sqrt{0.75(1-0.75)} }{0.08 }$

√n = $\frac{2 X0.4330}{0.08} = 10.825$

squaring on both sides , we get

n = 117.07

Final answer:-

The large sample n = 117.07

6 0

3 years ago