Copernicus's heliocentric theory stated that the planets orbited in perfectly circular orbits. In reality, they are shaped like ellipses (ovals).
Astronomers find white dwarfs that distinguish them from main sequence stars because white dwarfs get really hot, we can search for their ultraviolet radiation.
<h3>What is a white dwarf?</h3>
A white dwarf is a very hot star that radiated much energy in the form of ultraviolet radiation.
This UV radiation is initially very bright and then these stars become red with time.
In conclusion, Astronomers find white dwarfs they can search for their ultraviolet radiation.
Learn more about white dwarfs here:
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The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.
Answer:
Speed = 72.76mph
Explanation:
east direction signifies +
Therefore,
1515E -1125(45) = -2640
F = -2640×0.75 = -1980lbs
so,
-1980lbs = Ma
but m = 2640×g where g = 32.2 ft/s²
so,
a = -(1980/2640g) = -0.75×g = -24.15ft/s² = dv/dt
0 = V-24.15t
V =24.15t
22.5 = Vt -12.07t²
22.5 = 24.15t² - 12.07t² = 12.07t²
t = 1.37 seconds
Therefore,
V = 24.15 × 1.37 seconds = 33.1 ft/s
converting to mph gives
33.1 ft/s = 22.6 mph
now back to momentum
1515 E -1125(45) = 2640 V
1515 E = 50625+59664
Speed = 72.76 mph
1) See attached graph
To solve this part of the problem, we have to keep in mind the relationship between current and charge:
where
i is the current
Q is the charge
t is the time
The equation then means that the current is the rate of change of charge over time.
Therefore, if we plot a graph of the charge vs time (as it is done here), the current at any time will be equal to the slope of the charge vs time graph.
Here we have:
- Between t = 0 and t = 2 s, the slope is , so the current is 25 A
- Between t = 2 s and t = 6 s, the slope is , so the current is -25 A
- Between t = 6 s and t = 8 s, the slope is , so the current is 25 A
Plotting on a graph, we find the graph in attachment.
2)
The relationship we have written before
Can be rewritten as
This is valid for a constant current: if the current is not constant, then the total charge is simply equal to the area under the current vs time graph.
Therefore, we need to find the area under the graph.
Here we have a trapezium, where the two bases are
A = 1 ms = 0.001 s
B = 2 ms = 0.002 s
And the height is
h = 10 mA = 0.010 A
So, the area is
So, the charge is .