As an egg falls towards the floor, it begins to travel faster and faster. When it slams into the floor, the egg is stopped almost immediately. This force of the floor against the eggshell is too large, so it breaks.
Answer:
120,000
Explanation:
Millimeters to meters calculation-
Multiply by 1,000.
120 x 1,000 = 120,000.
This is the correct answer and formula.
Hope this helps!
The weight is 45 N, because the three chains hold the sign, and each contributes 15 N.
Notice that the mass would be the weight/acceleration of gravity, m = 45/9.8 kg. But they ask the weight (force, so Newtons)
Hi there!
![\large\boxed{\text{B) 20 meters}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Ctext%7BB%29%2020%20meters%7D%7D)
We know that:
![E_T = U + K](https://tex.z-dn.net/?f=E_T%20%3D%20U%20%2B%20K)
U = Potential Energy (J)
K = Kinetic Energy (J)
E = Total Energy (J)
At 10m, the total amount of energy is equivalent to:
U + K = 50 + 50 = 100 J
To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:
100J = mgh
We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².
50J = 10(10)m
m = 1/2 kg
Now, solve for height given that E = 100 J:
100J = 1/2(10)h
100J = 5h
<u>h = 20 meters</u>
Answer:
12.5 m/s
Explanation:
The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
Where, taking downward as positive direction, we have:
s = 8 m is the displacement of the hammer
u = 0 is the initial velocity (it is dropped from rest)
v is the final velocity
is the acceleration of gravity
Solving the equation for v, we find the final velocity:
![v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(8)}=12.5 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bu%5E2%2B2as%7D%3D%5Csqrt%7B0%2B2%289.8%29%288%29%7D%3D12.5%20m%2Fs)
So, the final speed is 12.5 m/s.