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Iteru [2.4K]
3 years ago
10

Which of the following sets shows all the numbers from the set {2, 3, 4, 5 that are part of the solution inequality 4n + 6> 2

2
Mathematics
1 answer:
harina [27]3 years ago
4 0
<h3>{ 5 } shows all the numbers from the set {2, 3, 4, 5 }that are part of the solution inequality 4n + 6> 22</h3>

<em><u>Solution:</u></em>

<em><u>Given inequality is:</u></em>

4n + 6 > 22

<em><u>Substitute n = 2</u></em>

4(2) + 6 > 22\\\\8 + 6 > 22

14 is not greater than 22

Thus, n = 2 does not satisfy the given equation

<em><u>Substitute n = 3</u></em>

4(3) + 6 > 22

12 + 6 > 22

18 is not greater than 22

Thus, n = 3 does not satisfy the given equation

<em><u>Substitute n = 4</u></em>

4(4) + 6 > 22

16 + 6 > 22

22 is equal to 22

Thus, n = 4 does not satisfy the given equation

<em><u>Substitute n = 5</u></em>

4(5) + 6 > 22

20 + 6 > 22

26 > 22

26 is greater than 22

Thus, n = 5 satisfies the given equation

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A rectangle's width is 1/3 its length and its perimeter is 40 m. find the dimensions of the rectangle
Rina8888 [55]

Answer:

Length = 15m

Width = 5m

Step-by-step explanation:

w = 1/3l

p = 2l + 2/3l

40 = 2 2/3 l

l = 15

w = 1/3(15)

w = 5

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
3 years ago
MS Nelson had 5,280 craft sticks. She gave all of the craft sticks to her 22 students. Each student received the same number of
ivanzaharov [21]
240 and can i get brainlist?
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3 years ago
Read 2 more answers
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
I need major help pleaseeeeeeeeeeeeee
sveta [45]
Just make a triangle and an X and Y axis and reflect it over the Y axis.  It's that simple.  Then tell how you did it.  Obviously it will be a reflection.  Name the points (before and after) and you are done.

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4 0
3 years ago
18) Mala gave Kamala half the number of sweets she had. She then had 7 sweets left. How many sweets did Mala have at the start?​
bixtya [17]

Answer:

Mala had 14 sweets at the start.

Step-by-step explanation:

7 x 2 = 14

To check, 14/2 = 7. (Dividing by 2 is the same as multiplying by 1/2)

4 0
3 years ago
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