Answer:
x=1
Step-by-step explanation:
We have,
h(x) = 5-2x
h(x)=3
Now,
h(x)=5-2x=3
or,5-2x=3
or,5-3=2x
or,2/2=x
Therefore, x=1 when h(x)=3
The last one (0,0) the middle of the graph is always (0,0)
The geometric series is convergent and the value is 16.
<h3>How to illustrate the information?</h3>
Recall that the sum of an infinite geometric series, S, given first term, t_1, and common ratio, r, is given by:
S = t_1/(1 - r)
Note that:
3 = (4)(3/4)
9/4 = (3)(3/4)
27/16 = (9/4)(3/4)
So this a geometric series with t_1 = 4 and r = 3/4. Therefore:
4 + 3 + 9/4 + 27/16 + ... = 4/(1 - 3/4) = 4/(1/4) = 16
The correct option is 16.
Learn more about geometric series on:
brainly.com/question/24643676
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Determine whether the geometric series is convergent or divergent. If it is convergent, find its sum
4+3+ 9/4 +27/16 +???
choices are
1. 3/4
2. 12
3. 4
4. divergent
5. 16
Answer: y = 3 (x -4)^3
Step-by-step explanation: horizontal shift of 4 units to the right (subtract 4 units from the x): y = 3(x - 4)^3
Vertical shift 3 units down (subtract 3 units from the function): y = 3(x - 4)^3 - 3
Answer: i don't know but thanks for the points
Step-by-step explanation:
