Classify triangle ABC by its sides if side AB = 6x, side AC = 4x + 6 and side BC = 8x + 3. The perimeter of triangle ABC is 63.
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2 answers:
Answer:
AB = 18
AC = 18
BC = 27
Step-by-step explanation:
Solve for x first:
6x + 4x + 6 + 8x + 3 = 63
6x + 4x + 8x + 6 + 3 = 63
18x + 9 = 63
18x = 63 - 9
18x = 54
x = 54 / 18
x = 3
Now substitute x to all sides.
AB = 6x
6(3) = 18
AC = 4x + 6
4(3) + 6
12 + 6 = 18
BC = 8x + 3
8(3) + 3
24 + 3 = 27
18 + 18 + 27 = 63
63 = 63
6x + 4x+6 + 8x+3 = 63
6x+4x+8x = 63 - 3 - 6
18x = 54
x = 54/18
x = 3
Side AB = 6(3) = 18
Side AC = 4(3)+6 = 18
Side BC = 8(3)+3 = 27
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Here are the CORRECT answers.
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The answer will be x= -3/5
Surface area of a ball:
S=4πr^2=4*π*5^2=100π
Volume of a circle:
V=4/3*π*r^3=4/3*π*125=(500/3)*π=165π
The approximate surface-area-to-volume ratio would be 1:1,5
Fraction 44/100
Decimal .44
Percent 44%
