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3 years ago

Bethany is 62 in tall Bethany's brother scott is 3 inches taller than her she is write Scott's height in feet and inches

1 answer:

8 0

Scott is 62+3=65 inches tall, and there are 12 inches in a foot, so you get 65/12=about 5 whole feet. 5 whole feet is 60 inches in total, so we have a leftover 5 inches, meaning that Scott is 5 feet and 5 inches tall.

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Select the solution(s) of the original equation. 3+ √21/2+4 3+ √21/2-4 3- √21/2+4 3-√21/2-4

jarptica [38.1K]

Answer:

2nd and 4th on edg

Step-by-step explanation:

3+21pi / 2 +4

3-21pi / 2 -4

4 0

2 years ago

Read 2 more answers

Julie wants to purchase a new home in six years. She thinks that she can purchase a nice home in a good neighborhood for $60,000

MrMuchimi

Answer:

$208.33

Step-by-step explanation:

Julie has to make the down payment which is 25% of $60000 after saving for 6 years.

Therefore, Julie has to save a total of $60000 \times \frac{25}{100} = 15000$ dollars.

And Julie has to save it for the duration of 6 years i.e. (6 × 12) = 72 months.

Hence, Julie has to save $\frac{15000}{72} = 208.33$ dollars every month to make the down payment after 6 years. (Answer)

7 0

3 years ago

What is the slope of the line that passes through: (6,5) and (-1,-4) Thank You!

My name is Ann [436]

Answer:

$m=\frac{9}{7}$

Step-by-step explanation:

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Simply plug in the 2 coordinates into the slope formula to find slope m:

$m=\frac{-4-5}{-1-6}$

$m=\frac{-9}{-7}$

$m=\frac{9}{7}$

6 0

3 years ago

A rectangular swimming pool is bordered by a concrete patio. the width of the patio is the same on every side. the area of the s

andre [41]

Answer:

$x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)$

where

l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Explanation:

Let

x = width of the patio
l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Since the pool is bordered by a complete patio,

Length of the pool (with the patio)
= (length of the pool (w/o the patio)) + 2*(width of the patio)
Length of the pool (with the patio) = l + 2x

Width of the pool (with the patio)
= (width of the pool (w/o the patio)) + 2*(width of the patio)
Width of the pool (with the patio) = w + 2x

Note that

Area of the pool (w/o the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
Area of the pool (w/o the patio) = lw

Area of the pool (with the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
= (l + 2x)(w + 2x)
= w(l + 2x) + 2x(l + 2x)
= lw + 2xw + 2xl + 4x²
Area of the pool (with the patio) = 4x² + 2x(l + w) + lw

Area of the patio
= (Area of the pool (with the patio)) - (Area of the pool (w/o the patio))
= (4x² + 2x(l + w) + lw) - lw
Area of the patio = 4x² + 2x(l + w)

Since the area of the patio is equal to the area of the surface of the pool, the area of the patio is equal to the area of the pool without the patio. In terms of the equation,

Area of the patio = Area of the pool (w/o the patio)
4x² + 2x(l + w) = lw
4x² + 2x(l + w) - lw = 0 (1)

Let

a = numerical coefficient of x² = 4
b = numerical coefficient of x = 2(l + w)
c = constant term = -lw

Then using quadratic formula, the roots of the equation 4x² + 2x(l + w) - lw = 0 is given by

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\\ = \frac{-2(l + w) \pm \sqrt{(2(l + w))^2 - 4(4)(-lw)}}{2(4)} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l + w)^2) + 16lw}}{8} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2) + 4(4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2 + 4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 6lw + w^2)}}{8}$
$= \frac{-2(l + w) \pm 2\sqrt{l^2 + 6lw + w^2}}{8} \\= \frac{2}{8}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\x = \frac{1}{4}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right) \text{ or }}
\\\boxed{x = -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

Since $(l + w) + \sqrt{l^2 + 6lw + w^2} \ \textgreater \ 0$ , $-\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2}\right)$ is negative. Since x represents the patio width, x cannot be negative. Hence, the patio width is given by

$\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

7 0

3 years ago

Solving and graphing systems of equations

dusya [7]

Hey Jackson!

-4x + 3y = 3
y = 2x + 1

Ok so what we need to do is solving y= 2x + 1 for y.

So let's start by using the substitution method :)

Substitute 2x + 1 for y in -4x + 3y = 3

-4x+ 3y = 3

-4x + 3(2x + 1) = 3

-4x + (3)(2x) + (3)(1) = 3

-4x + 6x + 3 = 3

2x + 3 = 3

Subtract 3 on both sides

2x + 3 - 3 = 3 - 3

2x = 0

x = 0/2

x = 0

So now since we find the number for x, we gonna use it to help us find the value for y.

To find y, we need to substitute 0 for x in y = 2x + 1

y = 2x + 1

y = 2(0) + 1

y = 0 + 1

y = 1

Thus,

The answer is: y = 1 and x = 0

How to graph?

You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1

I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)

Let me know if you have any questions. As always, it is my pleasure to help students like you!

3 0

3 years ago