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pickupchik [31]
4 years ago
6

b. Determine the molecular formula of a molecule with an empirical formula NH2and a molar mass of 32 g/mol.

Chemistry
1 answer:
VladimirAG [237]4 years ago
5 0
I'm taking this lesson now, so imma help u ( if u need anything else ask me)

so given Molar mass= 32 g/mol
molar mass= (empirical formula) n
32 = (14x1 + 2x1) n
32 = 16 n , so n= 2
so, molecular formula= N2H4
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Which group on the Periodic Table reacts violently with water by igniting hydrogen gas?
Artemon [7]

Answer:

the answer would be Halogens

4 0
3 years ago
A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t
pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = pK_a=9.31

First we have to calculate the moles of HCN and NaCN.

\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole

and,

\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole

The balanced chemical reaction is:

                          HCN+NaOH\rightarrow NaCN+H_2O

Initial moles     0.1116       0.0461     0.08978

At eqm.       (0.1116-0.0461)    0       (0.08978+0.0461)

                        0.0655                       0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=9.31+\log (\frac{0.1359}{0.0655})

pH=9.63

Therefore, the pH of the solution is, 9.63

4 0
3 years ago
What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon
Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles

\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles

Al_2O_3+3C\rightarrow 2Al+3CO  

According to stoichiometry :

1 mole of Al_2O_3 require 3 moles of C

Thus 0.59 moles of Al_2O_3 will require=\frac{3}{1}\times 0.59=1.77moles  of C

Thus Al_2O_3 is the limiting reagent as it limits the formation of product and C is the excess reagent as it is present in more amount than required.

As 1 mole of Al_2O_3 give = 2 moles of Al

Thus 0.59 moles of Al_2O_3 give =\frac{2}{1}\times 0.59=1.18moles  of Al

Mass of Al=moles\times {\text {Molar mass}}=1.18moles\times 27g/mol=31.8g

Thus 31.8 g of Al will be produced from the given masses of both reactants.

5 0
3 years ago
In some reactions, Be behaves like a typical alkaline earth metal; in others, it does not. Complete and balance the following: (
mina [271]

The correct answer is BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-.

Evaluating be behavior to see :

how it differs from the other Group 2A (2) members.

In this reaction Be behaves like other alkaline earth metals

The complete equation can be given as

BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-

BeCl_2 tends to form a chloro bridged dimer in the vapour state, however at high temperatures of the order of 1200K, this dimer dissociates into the linear monomer.

BeCl_2 has a chain structure in its solid form. Each Be atom in this structure is surrounded by chlorine atoms, two of which are connected by conversion bonds and the remaining two by covalent coordinate connections. This chain structure is displayed.

To know more about BeCl₂(I) + Cl⁻ refer the link:

brainly.com/question/5017059

#SPJ4

4 0
2 years ago
What is the ratio of Al3+ ions to S2- ions in a neutral compound?
lawyer [7]
C
2 to 3


2 of al3-
And 3 of s2+
Equals 0
8 0
3 years ago
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