Answer:
The balanced chemical equation for this process:
![H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)](https://tex.z-dn.net/?f=H_2SO_4%28aq%29%2BCa%28OH%29_2%28s%29%5Crightarrow%202H_2O%28l%29%2BCaSO_4%28aq%29)
$194.51 is the cost that the firm will incur from this use of slaked lime.
Explanation:
The balanced chemical equation for this process
![H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)](https://tex.z-dn.net/?f=H_2SO_4%28aq%29%2BCa%28OH%29_2%28s%29%5Crightarrow%202H_2O%28l%29%2BCaSO_4%28aq%29)
Moles of sulfuric acid = n
Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L
1 gallon = 3.785 Liter
Morality of the sulfuric acid = M = 1.05 m
![Molarity(M)=\frac{n}{V(L)}](https://tex.z-dn.net/?f=Molarity%28M%29%3D%5Cfrac%7Bn%7D%7BV%28L%29%7D)
![n=m\times V=1.05 M\times 4,542 L=4,769.1 mol](https://tex.z-dn.net/?f=n%3Dm%5Ctimes%20V%3D1.05%20M%5Ctimes%204%2C542%20L%3D4%2C769.1%20mol)
According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;
of calcium hydroxide
Mass of 4,769.1 moles of calcium hydroxide:
4,769.1 mol 74 g/mol = 352,913.4 g
= ![\frac{352,913.4 }{453.6} pounds =778.03 pounds](https://tex.z-dn.net/?f=%5Cfrac%7B352%2C913.4%20%7D%7B453.6%7D%20pounds%20%3D778.03%20pounds)
(1 pound = 453.6 grams)
Cost of 1 pound of slaked lime = $0.25
Cost of 778.03 pounds of slaked lime = $0.25 × 778.03 = $194.51
$194.51 is the cost that the firm will incur from this use of slaked lime.