Lpg contains ethane,propane,and butane..hope it helps
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Answer:
12.8 g of
must be withdrawn from tank
Explanation:
Let's assume
gas inside tank behaves ideally.
According to ideal gas equation- 
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin scale.
We can also write, 
Here V, T and R are constants.
So,
ratio will also be constant before and after removal of
from tank
Hence, 
Here,
and 
So, 
So, moles of
must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of
= 32 g/mol
So, mass of
must be withdrawn = 
Answer:
9g
Explanation:
Since..., Density = mass/volume
;Firstly calculate the volume change of the water when the metal is placed in,
;Volume = 26.47 - 21.25
;Volume = 5.22 mL
Hence the mass of the ore;
; Making mass the subject of formula in the above equation,
Mass = Density × Volume
; Mass = 1.72 × 5.22
; Hence the mass = 8.9784
= 9g
1. air components change from place to place, while water will just stay the same
2. Water doesn't have nor show individual properties, but air does show that it has it's own property
3. You can separate different gases from air physically, but with water you must pass electricity through it.
Don't take my word for it, this is just what I learned back in middle school.