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kramer
3 years ago
13

. The net ionic equation for the reaction that occurs during the titration of nitrous acid with sodium hydroxide is (a) HNO2 Na

1 OH-1 NaNO2 H2O (b) HNO2 NaOH Na 1 NO2-1 H2O (c) H 1 OH-1 H2O (d) HNO2 H2O NO2-1 H3O 1 (e) HNO2 OH-1 NO2-1 H2O
Chemistry
1 answer:
hjlf3 years ago
6 0

Answer:

H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Only the species which are present in aqueous state dissociate.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a)

The balanced molecular equation will be,

HNO_2_{(aq)}+NaOH_{(aq)}\rightarrow H_2O_{(l)}+NaNO_2_{(aq)}

The complete ionic equation in separated aqueous solution will be,

H^+_{(aq)}+NO_2^-_{(aq)}+Na^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+Na^+_{(aq)}+NO_2^-_{(aq)}

In this equation the species present are, Na^+\text{ and }NO_2^- are the spectator ions.

Hence, the net ionic equation contains specie is  

H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}

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How many grams of barium sulfate form when 35.0 ml of 0.160 m barium chloride reacts with 58.0 ml of 0.065 m sodium sulfate? do
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Barium sulfate weighs 0.88 grams per gram.

Mass:

A physical body's overall composition is measured by its mass.

Inertia, or the body's resistance to acceleration in the presence of a net force, is also measured by it.

The mass of a thing also affects how strongly it attracts other bodies through gravity.

In the SI, the kilogram serves as the basic mass unit (kg).

This information

Moles of BaCl2 equal 5.6 x 103 (35 x 0.160 / 1000)

sodium sulfate moles equal 58 x 0.065, or 3.77 x 103,

Na2SO4 with BaCl2 ——————————-> 2NaCl plus BaSO4

Na2SO4 is the limiting agent here.

Therefore, the product relies on limiting reagent.

1 mol of Na2SO4 produces 1 mol of BaSO4.

0.00377 moles of BaSO4 is one mole.

moles = mass / molar mass of BaSO4.

0.00377 = mass / 233.4

BaSO4 mass is 0.88 g.

So, 0.88 grams of barium sulfate make up one gram.

To know more about the mass visit:

brainly.com/question/28204586

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