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kramer
3 years ago
13

. The net ionic equation for the reaction that occurs during the titration of nitrous acid with sodium hydroxide is (a) HNO2 Na

1 OH-1 NaNO2 H2O (b) HNO2 NaOH Na 1 NO2-1 H2O (c) H 1 OH-1 H2O (d) HNO2 H2O NO2-1 H3O 1 (e) HNO2 OH-1 NO2-1 H2O
Chemistry
1 answer:
hjlf3 years ago
6 0

Answer:

H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Only the species which are present in aqueous state dissociate.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a)

The balanced molecular equation will be,

HNO_2_{(aq)}+NaOH_{(aq)}\rightarrow H_2O_{(l)}+NaNO_2_{(aq)}

The complete ionic equation in separated aqueous solution will be,

H^+_{(aq)}+NO_2^-_{(aq)}+Na^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+Na^+_{(aq)}+NO_2^-_{(aq)}

In this equation the species present are, Na^+\text{ and }NO_2^- are the spectator ions.

Hence, the net ionic equation contains specie is  

H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}

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Vesnalui [34]

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M

Which is also:

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Thereafter we can compute the pOH first:

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Finally, the pH turns out:

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Regards!

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