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g100num [7]
2 years ago
11

__________ described atoms as having a positive nucleus with electrons that have different energies at different distances from

the nucleus.
Option that go in the blank:
Bohr or Dalton or Rutherford or Thomson pick one
Chemistry
1 answer:
Aloiza [94]2 years ago
5 0

Answer:

Niels Bohr

Explanation:

Niel’s Bohr described the atomic model. He in his model showed that an atom is a small positively charged nucleus. Around the positively charged nucleus, electrons orbit in separate orbits.  

The electrons in the outermost shell are responsible for the  properties associated with an element.  

The electrons at different shells have different energy. When an electron jumps from a shell of higher energy to a shell of lower energy, energy is released.  

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Why would dry cleaners use nonpolar tetrachloroethylene, C2Cl4, to get cheeseburger grease out of your clothes?
Kobotan [32]

It is water-soluble. hope this helps


6 0
3 years ago
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Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

6 0
2 years ago
Kumar is producing the photoelectric effect by using red light. He wants to increase the energy of emitted electrons. Based on t
aliya0001 [1]
He has to use a different colored light at a higher frequency.
3 0
3 years ago
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How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?
stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using  ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0
3 years ago
How many liters are in 5.42 mols of O2 gas?<br><br> (2 decimal places)
Debora [2.8K]

Explanation:

1 mol = 22.4 l

5.42 mol = 22.4 × 5.42 = 121.408

in two decimal place it is 121.41

7 0
3 years ago
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