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Flura [38]
3 years ago
5

What contributes to the lethargic feeling when riding in a car for long periods of time? Could inertia play into it? Looking for

the scientific explanation of how movement affects the body.
Physics
1 answer:
irinina [24]3 years ago
8 0

Exactly the same reason babies' cradles are built on curved runners, for rocking, and why we put the baby in a swing or rock the baby to sleep in our arms.  We are hard-wired to become soothed and relaxed by gentle repetitive motion.

But that still isn't an explanation of "Why".  My own understanding is that this is a carry-over from the earliest stages of our brain formation, when we were suspended in a pool of warm fluid in utero and our mother walked around during the normal activity of her normal day.

In my own personal case, I could never be an aircraft pilot.  As soon as my seat-belt is buckled and the airplane starts bobbing up and down, even while still on the ground, I am out cold.  I seldom remember take-off.  I have been on commercial business flights, that lasted 18 hours and I slept through 16 of them.  Turbulence in flight is even better.  If I happen to be awake, flying into a storm will knock me out in seconds.  

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Suppose you have a total charge qtot that you can split in any manner. Once split, the separation distance is fixed. How do you
dybincka [34]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know from the Coulomb's Law that, Coulomb's force is directly proportional to the product of two charges q1 and q2 and inversely proportional to the square of the radius between them.

So,

F = \frac{Kq1q2}{r^{2} }

Now, we are asked to get the greatest force. So, in order to do that, product of the charges must be greatest because the force and product of charges are directly proportional.

Let's suppose, q1 = q

So,

if q1 = q

then

q2 = Q-q

Product of Charges = q1 x q2

Now, it is:

Product of Charges = q x (Q-q)

So,

Product of Charges = qQ - q^{2}

And the expression qQ - q^{2} is clearly a quadratic expression. And clearly its roots are 0 and Q.

So, the highest value of the quadratic equation will be surely at mid-point between the two roots 0 and Q.

So, the midpoint is:

q = \frac{Q + 0}{2}

q = Q/2 and it is the highest value of each charge in order to get the greatest force.

8 0
3 years ago
A mass is hung from a spring and set in motion so that it oscillates continually up and down. The velocity v of the weight at ti
otez555 [7]

To solve the problem it is necessary to identify the equation in the manner given above.

This equation corresponds to the displacement of a body under the principle of simple harmonic movement.

Where,

\xi = Acos(\omega t +\phi)

PART A) Our equation corresponds to

y = -5cos(4\pi t)

Therefore the value of omega is equivalent to that of

\omega = 4\pi

From the definition we know that the period as a function of angular velocity is equivalent to

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{4\pi}

T = \frac{1}{2}

This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the cos\thetaIs equivalent to . So the maximum speed that the body can reach is,

y = -5cos(4\pi t)

y = -5cos(4\pi (1/2))

y = -5*(-1)

y = 5

Therefore the maximum felocity will be 5ft / s

PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then

t = \frac{T}{2} = \frac{1}{2}*\frac{1}{2}

t = \frac{1}{4}s

5 0
3 years ago
A straight wire lies along the y-axis initially carrying a current of 10 A in the positive y-direction. The current decreases an
Elan Coil [88]

Answer:

Explanation:

The magnetic field due to straight wire is into the square coil.

As the current in straight wire decreases the magnetic flux in the coil decreases . The induced magnetic field is into the coil.The induced current is along +y direction

8 0
4 years ago
An Apple falls from a tree and one-half second later hits the ground
docker41 [41]
There isnt enough information to answer the question, the missing variable is "distance from said falling spot and ground"
8 0
3 years ago
If you wish to observe features that are around the size of atoms, say 5.5 × 10^-10 m, with electromagnetic radiation, the radia
Tanya [424]

Answer:

a) 5.5×10^17 Hz

b) visible light

Explanation:

Since the wavelength of the electromagnetic radiation must be about the size of the about itself, this implies that;

λ= 5.5 × 10^-10 m

Since;

c= λ f and c= 3×10^8 ms-1

f= c/λ

f= 3×10^8/5.5 × 10^-10

f= 5.5×10^17 Hz

The electromagnetic wave is visible light

3 0
4 years ago
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