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gizmo_the_mogwai [7]
3 years ago
6

A conducting strip of width 1.5 mm is in a magnetic field. As a result, there is a potential difference of 4.3 mV across the wid

th of the strip. What is the magnitude of the electric field in the strip
Physics
1 answer:
OLga [1]3 years ago
6 0

To solve this problem we will apply the concepts related to the Voltage depending on the Electric field and the distance where it is applied. The relationship of this relationship is given in the following form:

V= Ed \rightarrow E = \frac{V}{d}

Here,

E = Electric Field

V = Voltage

d = Distance

Our values are given as,

d = 1.5mm = 1.5*10^{-3} m

V = 4.3 mV

V = 4.3*10^{-3}V

Replacing at the first equation we have,

E = \frac{4.3*10^{-3}}{1.5*10^{-3}}

E = 2.866V/m

Therefore the electric field in the strip is 2.866V/m

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Answer:

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

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Given that :m=13.0kg, \ L=0.14m, \ F(t)=6sin\frac{t}{2}N, F_d(t*)=-4N^{-1}, u\prime(t*)=0.12m/s\\u(0)=0,u\prime(0)=0.04m/s

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13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\, u in meters,t in seconds.

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