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3 years ago

If there is gravity on earth than why don't the birds and clouds fall down?

Physics

2 answers:

iogann1982 [59]3 years ago

6 0

Answer:

Birds don't fall down when they fly because their wings build lift when they flap them. Clouds don't fall down because the water particles that they keep are spread out for miles, so gravity has little effect on them.

Tju [1.3M]3 years ago

6 0

For the same reason that you're able to walk up the stairs when you feel like it. A force is used that works in the direction opposite to gravity and exceeds it.

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I need help with this problem on science 8th grade here is the picture of the assignment place help me

Leni [432]

Answer:

the first one is D

Explanation:

so if the others u put are right the the second would be c

7 0

3 years ago

Read 2 more answers

If i try to fail and succeed which one did I do

Novay_Z [31]

You've failed because you failing becomes a statement rather than it becoming fact or what actually happened.

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3 years ago

In 1986, several robotic spacecrafts were sent into space to study the Halley's Comet. Which of these statements best explains w

Archy [21]

<span>c. They help discard some myths about objects in space.

When we learn something new, then we know more stuff,
and that helps us avoid ignorance and superstition.

The REAL question is:
</span><span>Why should we continue to send robotic spacecrafts,
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3 years ago

The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr

WARRIOR [948]

In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
$y_n= \frac{n \lambda D}{a}$ (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
$\lambda$ is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem,
$D=37.0 cm=0.37 m$
$\lambda=530 nm=5.3 \cdot 10^{-7} m$
while the distance between the first and the fifth minima is
$y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m$ (2)

If we use the formula to rewrite $y_5, y_1$ , eq.(2) becomes
$\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m$
Which we can solve to find a, the width of the slit:
$a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}= 1.57 \cdot 10^{-3} m=1.57 mm$

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4 years ago

Set the initial bead height to 3.00 m. Click Play. Notice that the ball makes an entire loop. What is the minimum height require

strojnjashka [21]

Answer:

h> 2R

Explanation:

For this exercise let's use the conservation of energy relations

starting point. Before releasing the ball

Em₀ = U = m g h

Final point. In the highest part of the loop

Em_f = K + U = ½ m v² + ½ I w² + m g (2R)

where R is the radius of the curl, we are considering the ball as a point body.

I = m R²

v = w R

we substitute

Em_f = ½ m v² + ½ m R² (v/R) ² + 2 m g R

em_f = m v² + 2 m g R

Energy is conserved

Emo = Em_f

mgh = m v² + 2m g R

h = v² / g + 2R

The lowest velocity that the ball can have at the top of the loop is v> 0

h> 2R

3 0

3 years ago

If there is gravity on earth than why don't the birds and clouds fall down? ​

If there is gravity on earth than why don't the birds and clouds fall down?