A. the heat added represents an energy change
For a pipe closed at one end, the second overtone is the 3rd natural frequency as shown in the diagram.
For the fundamental frequency,
λ = 4L
where
λ = wavelength
L = the length of the tube
For the second overtone (3rd frequency)
λ = (4/3)L
Because L = 6.8 m, therefore
λ = (4/3)*(6.8 m) = 9.0667 m
The distance between a node and an adjacent antinode is λ/2, which is
9.0667/2 = 4.533 m
Answer: 4.5 m
Answer:
The density ρ of metal block is 8.92g/cm³
So from the given density table this corresponds to copper which has density of 8.92(g/mL)
Explanation:
Oh yeah, I got the correct unit update,
Now this problem bothers on the density of substances
We know that the density of a substance is expressed as
Density ρ= mass/ volume
Given data
Mass of metal block m= 62.44g
Volume of metal block v= 7 cm³
Hence we can find the density of the metal block by plugging in our data into the expression for density
ρ of metal block = 62.44/7
ρ of metal block = 8.92g/cm³
The block is a copper block
Answer:
1.37 ×10^-3 T
Explanation:
From;
B= μnI
μ = 4π x 10-7 N/A2
n= number of turns /length of wire = 1700/0.75 = 2266.67
I= 0.48 A
Hence;
B= 4π x 10^-7 × 2266.67 ×0.48
B= 1.37 ×10^-3 T
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