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Sauron [17]
3 years ago
12

Please help

Physics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

The two moments must be the same:

p1=p2

m1v1=m2v2

v2=(m1v1)/m2

v2=(90 kg x 0.9 m/s)/110kg=0.7 m/s

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How much force is needed to slow down a 15 kg car traveling at 60 m/s to 15 m/s in 10 seconds?​
goldfiish [28.3K]

Answer:

The force needed to slow down the car is, F = 67.5 N

Explanation:

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The initial velocity of the car, V = 60 m/s

The final velocity of the car, v = 15 m/s

The time period of deceleration, t = 10 s

The difference in the momentum of the car is,

                                     mV - mv = 15(60 - 15)

                                                    = 675 kg m/s

The rate of change in momentum of the car gives the force acting on it.

                                    F = (mV - mu) / t

Substituting the values,

                                   F = 675 / 10

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3 years ago
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