Answer:
<h2> The answer is </h2><h2>a. 5g/mL</h2>Explanation:
Given data
mass m= 45g
volume v= 9mL
we know that density=m/v
substituting our given data we have
What is Density?
The Density of a body can be defined as the ratio of mass to volume,
or
Density, mass of a unit volume of a material substance. The formula for density is ,
where d is density,
M is mass, and
V is volume.
Density is commonly expressed in units of grams per cubic centimetre.
Answer:
a) 24.33 m of distance.
b) 34.55° east of the south.
Explanation:
The question is incomplete. The whole exercise is the following:
<em>"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other. </em>
<em>(a) What is the distance between them? </em>
<em>(b) In what direction should Ricardo walk to go directly toward Jane?</em><em>"</em>
Now that we know what we need to do in this question, let's head for every part of the problem.
<u>a) Distance between Ricardo and Jane</u>
In this case, we need to analyze the given data:
Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).
Let's call the distance between them as "D", to get the distance of D, according to the picture will be:
D = J - R (1)
However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:
D = √Dx² + Dy² (2)
So, let's get the components of x and y of R and J.
For Ricardo (R):
Rx = R sin60° = 28 sin60° = -24.25 m
Ry = R cos60° = 28 cos60° = 14 m
The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.
For Jane (J):
Jx = J cos30° = 12 cos30° = -10.39 m
Jy = J sin30° = 12 sin30° = -6 m
Again, the negative is added because J is on the third quadrant.
Now that we have the components, let's calculate vector D using expression (1):
Dx = -10.39 - (-24.25) = 13.86 m
Dy = -6 - 14 = -20 m
Now, using expression (2) we can finally know the distance between Jane And Ricardo:
D = √(-20)² + (13.86)²
<h2>D = 24.33 m</h2>This is the distance between Jane and Ricardo.
b) Direction of Ricardo walking to Jane
In this case, we already have the components of x and y of the distance between them, so, to know the direction:
Tanα = Dy/Dx
α = tan⁻¹ (Dy/Dx)
Replacing the values we have:
α = tan⁻¹ (-20/13.86)
α = 55.45°
Which should south of east or:
β = 90 - 55.45
<h2>β = 34.55°</h2>Ricardo should walk 34.55° east of south
Hope this helps
To develop this problem it is necessary to use the expression that allows us to convert the degrees Celsius to Fahrenheit. The expression that allows to realize it is given mathematically by:
In this way for 33.2 °C:
In this way for 38.2°C
Expressed in a range term, we can say that the measure in degrees Fahrenheit is: