Answer:
17.6 m²
Step-by-step explanation:
Given the ratio of similar shapes = a : b, then
area of shapes = a ² : b²
Δ PTQ and Δ PRS are similar and so the ratio of corresponding sides are equal, that is
PT : PR = 6 : 9 = 2 : 3, thus
ratio of areas = 2² : 3² = 4 : 9
let the area of Δ PQT be x, then using proportion
= 
( cross- multiply )
9x = 4(x + 22) ← distribute
9x = 4x + 88 ( subtract 4x from both sides )
5x = 88 ( divide both sides by 5 )
x = 17.6
Thus area of Δ PQT = 17.6 m²
Answer:
<em>Option C; 3x - y = -27 and x + 2y = 16</em>
Step-by-step explanation:
1. Let us consider the equation 21x - y = 9. In this case it would be best to keep the equation in this form, in order to find the x and y intercept. Let us first find to y - intercept, for the simplicity ⇒ 21 * ( 0 ) - y = 9 ⇒ y = - 9 when x = 0. Now if we take a look at the first plot of line q, we can see that the x value is -9 rather than the y value, so this equation doesn't match that of line q. This would eliminate the first two options being a possibility.
2. Now let us consider the equation 3x - y = -27. Let us consider the x-intercept in this case. That being said, ⇒ 3x - ( 0 ) = -27 ⇒ 3x = -27 ⇒ x = -9 when y = 0. As we can see, this coordinate matches with one of the coordinates of line q, which might mean that the second equation could match with the equation for line v.
3. To see whether Option 3 is applicable, we must take a look at the 2nd equation x + 2y = 16. Let us calculate the y - intercept here: ( 0 ) + 2y = 16 ⇒ 2y = 16 ⇒ y = 8 when x = 0. Here we can see that this coordinate matches with that of the second coordinate provided as one of the points in line v. That means that ~ <em>Answer: Option C</em>
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Answer:
Step-by-step explanation:
2:3 boy:teacher 8:12
4:5 teacher:girl 12:15
8:12:15 boy:teacher:girl
It is given in the question that
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by
And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.
Here we differentiate V with respect to t, and we use product rule, that is
Substituting the given values , we will get
![[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)](https://tex.z-dn.net/?f=%5Btex%5DdV%2Fdt%20%3D%202%2812%29%286%29%28-2%29%2B%2012%5E2%281%29)
[/tex]
So at that moment, the volume is decreasing at the rate of
Answer:
No.
Step-by-step explanation:
No because if we substitute the given values into the equation they do not fit:
y = 7x
x = 1 and y = 4:
Left side = 4
right side = 7*1 = 7.
