For the time period of the projectile at least 192 feet above the ground is between 2 second and 6 second
Since s=128t-16t2, we want to know the 2 times where 128t-16t2=192, as those two values will be the begin and end times of the interval in question. We can rewrite that equation in standard quadratic equation form:
16t2-128t+192=0 or, simplified, 8t2-64t+96=0
or t2-8t+12=0
since it is now in quadratic form, we can solve using the quadratic formula:
t = 2 and 6
So the time period from approximately 2 second and 6 second has the projectile above 192 feet.
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The correct answer is B) y=80000(1.03)ˣ.
Population growth is represented using an exponential equation. These equations are of the form
y = a(1+r)ˣ, where y is the total population, a is the initial population, r is the growth rate, and x is the amount of time.
We first find the growth rate. This is the percent of change, which is found by
amount of change/original amount
The amount of change from 2010 to 2011 is 82400-80000=2400. 2400/80000 = 0.03, so r = 0.03.
The growth rate from 2011 to 2012 is (84872-82400)/82400 = 0.03. Checking the others, they are very close to this as well, so we will use this as r.
Our value of a in the equation is the initial population, 80000. This gives us:
y = 80000(1+0.03)ˣ = 80000(1.03)ˣ
Answer: Jerry paid £150000 for the house in 2003
Y = (x +7)^2. The parabola is going into the negative region. The x value must be positive.
Answer:
The time would become 13:40
Step-by-step explanation:
8 in 8:40 is hours
40 in 8:40 is minutes.