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Feliz [49]
3 years ago
6

The value of a plot of land is S18 000.00.

Mathematics
2 answers:
Brums [2.3K]3 years ago
7 0

Answer:

$126

Step-by-step explanation:

The plot of land is worth $18,000 and the tax on the land is $0.70 per $100. You would divide 18000 by 100 which is 180. Then you would multiply 180*0.70 which is $126.

Tju [1.3M]3 years ago
3 0

Step-by-step explanation:

Here, given that;

The total value of land us $18000.00

tax per $100.00 is $0.70

now,

$100.00 taxes $0.70

$18000.00 taxes ($18000.00÷100)/$0.70 (as in question given that the tax is charged in each $100)

= $126.

is the required tax amount.

<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em>

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A worker’s pay for one week was $312. She worked 39 hours. How much was she paid per hour?
Volgvan

To find out how much she earned hourly, all we need to do is divide 312 and 39

312 ÷ 39 = 8

Therefore, she was paid $8 per hour

Hope this helps!

8 0
3 years ago
Read 2 more answers
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Vinil7 [7]

Answer:

a)

X[bar]_A= 71.8cm

X[bar]_B= 72cm

b)

M.A.D._A= 8.16cm

M.A.D._B= 5.4cm

c) The data set for Soil A is more variable.

Step-by-step explanation:

Hello!

The data in the stem-and-leaf plots show the heights in cm of Teddy Bear sunflowers grown in two different types of soil (A and B)

To read the data shown in the plots, remember that the first digit of the number is shown in the stem and the second digit is placed in the leaves.

The two data sets, in this case, are arranged in a "back to back" stem plot, which allows you to compare both distributions. In this type of graph, there is one single stem in the middle, shared by both samples, and the leaves are placed to its left and right of it corresponds to the observations of each one of them.

Since the stem is shared by both samples, there can be observations made only in one of the samples. For example in the first row, the stem value is 5, for the "Soil A" sample there is no leaf, this means that there was no plant of 50 ≤ X < 60 but for "Soil B" there was one observation of 59 cm.

X represents the variable of interest, as said before, the height of the Teddy Bear sunflowers.

a) To calculate the average or mean of a data set you have to add all observations of the sample and divide it by the number of observations:

X[bar]= ∑X/n

For soil A

Observations:

61, 61, 62, 65, 70, 71, 75, 81, 82, 90

The total of observations is n_A= 10

∑X_A= 61 + 61 + 62 + 65 + 70 + 71 + 75 + 81 + 82 + 90= 718

X[bar]_A= ∑X_A/n_A= 218/10= 71.8cm

For Soil B

Observations:

59, 63, 69, 70, 72, 73, 76, 77, 78, 83

The total of observations is n_B= 10

∑X_B= 59 + 63 + 69 + 70 + 72 + 73 + 76 + 77 + 78 + 83= 720

X[bar]_B= ∑X_B/n_B= 720/10= 72cm

b) The mean absolute deviation is the average of the absolute deviations of the sample. It is a summary of the sample's dispersion, meaning the greater its value, the greater the sample dispersion.

To calculate the mean absolute dispersion you have to:

1) Find the mean of the sample (done in the previous item)

2) Calculate the absolute difference of each observation and the sample mean |X-X[bar]|

3) Add all absolute differences

4) Divide the summation by the number of observations (sample size,n)

For Soil A

1) X[bar]_A= 71.8cm

2) Absolute differences |X_A-X[bar]_{A}|

|61-71.8|= 10.8

|61-71.8|= 10.8

|62-71.8|= 9.8

|65-71.8|= 6.8

|70-71.8|= 1.8

|71-71.8|= 0.8

|75-71.8|= 3.2

|81-71.8|= 9.2

|82-71.8|= 10.2

|90-71.8|= 18.2

3) Summation of all absolute differences

∑|X_A-X[bar]_A|= 10.8 + 10.8 + 9.8 + 6.8 + 1.8 + 0.8 + 3.2 + 9.2 + 10.2 + 18.2= 81.6

4) M.A.D._A=∑|X_A-X[bar]_A|/n_A= 81.6/10= 8.16cm

For Soil B

1) X[bar]_B= 72cm

2) Absolute differences |X_B-X[bar]_B|

|59-72|= 13

|63-72|= 9

|69-72|= 3

|70-72|= 2

|72-72|= 0

|73-72|= 1

|76-72|= 4

|77-72|= 5

|78-72|= 6

|83-72|= 11

3) Summation of all absolute differences

∑ |X_B-X[bar]_B|= 13 + 9 + 3 + 2 + 0 + 1 + 4 + 5 + 6 + 11= 54

4) M.A.D._B=∑ |X_B-X[bar]_B|/n_B= 54/10= 5.4cm

c)

If you compare both calculated mean absolute deviations, you can see M.A.D._A > M.A.D._B. As said before, the M.A.D. summary of the sample's dispersion. The greater value obtained for "Soil A" indicates this sample has greater variability.

I hope this helps!

7 0
3 years ago
PLSSS HELP WILL GIVE BRAINLIEST FOR FIRST CORRECT ANSWER!!!!!!!!!
Kryger [21]

Answer:

A fair die has 6 sides.

There are 3 odd numbers on a fair die so the probability would be 3/6

There are 4 numbers greater than 2 on a fair die o the probability of that would be 4/6

There is only one number that will make it square and that is 4. So the probability would be 1/6

6 0
3 years ago
Teri ran 8 kilometers
viva [34]

Answer:

teri is tired

Step-by-step explanation:

from running

7 0
3 years ago
Make up this problem yourself 3 divided by 1/2
Helen [10]

Answer:

3 : (1/2) =\frac{6}{1} =6

Step-by-step explanation:

Divide: 3 : \frac{1}{2} =\frac{3}{1} *\frac{2}{1} =\frac{3 * 2}{1*1} =\frac{6}{1} =6

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of \frac{1}{2} is \frac{2}{1}) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.

In words - three divided by one half = six.

8 0
3 years ago
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