Answer:
Any points in the shaded region including (2,-2) and (-3,-8)
Step-by-step explanation:
Convert the line into slope intercept form and graph it.
2x-y > 1 becomes -y>1-2x. Divide both sides by -1 and you get y<2x-1. Graph it with the shaded area on the right and a dashed line.
Any point which falls within the shaded red of the graph is a solution. No points on the line since it is not equal to (its dashed) are solutions. Check the location of your points to verify that they fall within this area.
(-3, -8) ---Yes
(-1, -3) ---No
(0, 5) --- No
(1, 6) --- No
(2, -2) ---Yes
Answer:
boom
Step-by-step explanation:
Sorry I don’t see any images or diagrams I’m not sure
√16=4
Hope i could help. -\(-_-)/-
For this, there is two rules. The common slope-intercept form is y=ax + b. For parallel, b can change, but a, or the slope, can't change. But for perpendicular, the a should be -1/a, where the answer for times the original equation, or a, and the second equation, or -1/a, is -1. To prove these two rules, you can graph it using random numbers but follow these two rules. if you have any part that don't understand for this answer, feel free to ask in the "Ask for details" section.
