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MrRissso [65]
3 years ago
8

Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If Jason tosses the coin an eleven

th time, what is the probability that it will land on heads?
Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0
:Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If                                           Jason tosses the coin an eleventh time, what is the probability that it will land on heads?  
Solution:
​
The probability would be ½. The result of the eleventh toss does not depend on the previous                                   
results.  
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A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102
cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

<u>Given:</u>

<em>n</em> = 1000

\hat p = 0.102

z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

6 0
3 years ago
Can anyone help me with this last problem
mr_godi [17]
I believe your answer is C

8 0
3 years ago
 PLEASE HELP 15 points for brainliest! What is the solution of n^2-49=0
creativ13 [48]

Answer:  The correct option are (1). c, (2). d and (3). (b).

Step-by-step explanation:  The calculations are as follows:

(1) We are to find the solution of the following quadratic equation:

n^2-49=0.

We have

n^2-49=0\\\\\Rightarrow n^2=49\\\\\Rightarrow n=\pm7~~~~~\textup{[taking square roots on both sides]}

Thus, the correct option is (c). \pm7.

(2) We are to find the solution of the following quadratic equation:

x^2+64=0.

We have

x^2+64=0\\\\\Rightarrow x^2=-64.

Since there is no real number whose square is negative, so this equation has no solution.

Thus, the correct option is (d). no solution.

(3) We are given to find the side length of a square with an area of 144x².

Let, 'a' denotes the side length of the square.

Then,

a^2=144x^2\\\\\Rightarrow a=\pm12x.~~~~~~~\textup{[taking square root on both sides]}

Since the length of the side cannot be negative, so the side length is 12x.

Thus, (b) is the correct option.

The correct option are (1). c, (2). d and (3). (b).

6 0
3 years ago
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3 years ago
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Arithmetic sequences algebra
andreyandreev [35.5K]

As given arithmetic sequence is :-

-17 , -13 , -9

So, here we have to find a12

a ( 1st term ) = -17

d ( common difference) = a2 - a1

d = -13 -(-17)

d = 4

nth place = a12

Now we know that to find any term we apply formula :-

an = a + (n-1)d

So putting Values in above mentioned formula :-

a12 = -17 + ( 12-1) 4

a12 = -17 + (11)4

a12 = -17 + 44

<h3>a12 = 27 </h3>

Hope it helps

3 0
3 years ago
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