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Helen [10]
3 years ago
13

What is the range of the function on the graph?

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

The range is all real numbers greater than or equal to 2

Step-by-step explanation:

we know that

Observing the graph

The solution for the variable y is

y\geq 2

therefore

The range is the interval -----> [2,∞)

All real numbers greater than or equal to 2

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\text{Volume}=129.87cm^3

Explanation

Step 1

the density of an object is given by:

\text{density}=\text{ }\frac{mass}{\text{volume}}

Step 2

let

\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\  \end{gathered}

Step 3

replace,

\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\  \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}

I hope this helps you

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1 year ago
A=pi r^2 which if the following equations can be used to solve for the radius (r)
zhannawk [14.2K]
C. You would first have to divide A by Pi, then take the square root of r, in order to get r by itself.
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3 years ago
You divide a number and get a remainder of 4. what 1 - digit number can the divisor of the problem?
ahrayia [7]

Answer:

<em>Any of the numbers 5,6,7,8,9 could be the divisor of the problem.</em>

Step-by-step explanation:

<u>Division</u>

If I divide a number and get a remainder of 4, then the divisor must be greater than 4. A divisor of 4, for example, would lead to a remainder of (maximum) 3.

Thus, our divisor can only be one among the numbers: 5,6,7,8,9. If the dividend is exactly 4, then the divisions

4/5, 4/6, 4/7, 4/8, and 4/9

they all produce the same remainder of 4.

Thus, any of the numbers 5,6,7,8,9 could be the divisor of the problem

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3 years ago
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Answer:

Yes

Step-by-step explanation:

Reason is that a square has all the aspects of a parallelogram a rectangle and a rhombus. It gets its congruent diagonals from the rectangle which is congruent

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