What holds planets, stars, gas, and dust together in a galaxy?

you are driving along a country road when you suddenly notice a log in the road ahead of you and immediately apply your brakes.

DiKsa [7]

a. The car will not hit the tractor.

b. The car would travel a distance of 52.07 m before stopping

c. At the moment when the car stopped, the tractor is 11.5 m in front of the car.

Linear motion

From the question, we are to determine of you will hit the tractor before you stop

First, we will determine the time it will take the car to stop

From the given information,

Initial velocity, u = 27.0 m/s

a = -7 m/s² (Negative sign indicates deceleration)

v = 0 m/s (Since the car will come to stop)

From one of the equations of linear motion,

v = u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time taken

Putting the parameters into the equation, we get

0 = 27 + (-7)t

7t = 27

t = 27/7

t = 3.857 secs

This is the time it will take the car to stop

Now, we will determine the distance the car would travel after applying the brakes

Using the formula

S = (u + v) / t

Where S is the distance traveled

S = [(27 + 0) / 2] * 3.857

S = 13.5 * 3.857

S = 52.0695 m

S ≅ 52.07 m

This means the car would travel 52.07 m after applying the brakes

Now, we will determine the distance the tractor would have traveled when the car came to a stop

Speed of the tractor = 10.0 m/s

Time taken for the car to stop = 3.857 secs

Using the formula,

Distance = Speed × Time

Distance = 10.0 × 3.857

Distance = 38.57 m

Now, we will determine the distance between the car and the tractor when the car finally stopped

Distance between the car and the tractor = Distance ahead + Distance traveled by the tractor after the car stopped - Distance traveled by car after applying the brakes

Distance between the car and the tractor = 25 m + 38.57 m - 52.07 m

Distance between the car and the tractor = 11.5 m

Therefore, the distance the tractor was ahead of the car + the distance the tractor traveled after the car stopped is more than the distance the car traveled after applying the brakes (25 m + 38.57 m > 52.07), the car will not hit the tractor.

To know more about distance, refer: brainly.com/question/10903482

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: You are driving your car along a country road at a speed of 27.0 m/s. as you come over the crest of a hill, you notice a farm tractor 25.0 m ahead of you on the road, moving in the same direction as you at a speed of 10.0 m/s. you immediately slam on your brakes and slow down with a constant acceleration of magnitude 7.00 m/s2 .

a.will you hit the tractor before you stop?

b.how far will you travel before you stop or collide with the tractor?

c.if you stop, how far is the tractor in front of you when you finally stop?]

7 0

1 year ago

A nonconducting ring of radius 10.0 cm is uniformly charged with a total positive charge 10.0μC. The ring rotates at a constant

maw [93]

The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.

The radius of the nonconducting ring is R = 10 cm.

The ring is uniformly charged q = 10 μC.

The angular speed of the ring, ω = 20 rad/s

The ring is x = 5 cm from the center of the ring.

Now,

R = 10 cm = 0.1 m

q = 10.0 μC = 10 × 10⁻⁶ C

x = 5 cm = 0.05 m

The magnetic field on the axis of a current loop is given as:

B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]

Now, I = q / [2π/ω]

So, the magnitude of the magnetic field which is directed away from the center is:

B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]

B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]

B = 1.43 × 10⁻¹⁰ T

B = 143 pT

Learn more about the magnetic field here:

brainly.com/question/14411049

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3 0

2 years ago

1. How is electric potential energy similar to gravitational potential energy? How is it different? Where will an electron bound

Korolek [52]

Both ve similar equations
both are energies of one object w.r.t another 
differences- electric pe is due to electrostatic force and gravitational pe is due to gravitational force 
electric pe is > than gravitational pe since electrostatic force> gravitational force 
electron bound in an atom ll ve largest potential enegy in its ground state. i think hope it helps

7 0

3 years ago

A 12-V battery maintains an electric potential difference between two parallel metal plates separated by 10 cm. What is the elec

Sauron [17]

Answer:

The electric field between the plates is 120 V/m.

(c) is correct option.

Explanation:

Given that,

Potential difference = 12 volt

Distance = 10 cm = 0.1 m

We need to calculate the electric field between the plates

Using formula of electric field

$E = \dfrac{V}{d}$

Where, V = potential difference

d = distance between the plates

Put the formula

$E =\dfrac{12}{0.1}$

$E=120\ V/m$

Hence, The electric field between the plates is 120 V/m.

4 0

4 years ago

As it heats, fluid _____. A) Rises B) Compacts USA TEST PREP!!

timofeeve [1]

Answer:

Rises.

Explanation:

Convection causes the heated liquid to rise.

4 0

4 years ago