A 12-V battery maintains an electric potential difference between two parallel metal plates separated by 10 cm. What is the elec
1 answer:
Answer:
The electric field between the plates is 120 V/m.
(c) is correct option.
Explanation:
Given that,
Potential difference = 12 volt
Distance = 10 cm = 0.1 m
We need to calculate the electric field between the plates
Using formula of electric field
Where, V = potential difference
d = distance between the plates
Put the formula
Hence, The electric field between the plates is 120 V/m.
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Answer : .
Explanation:
It is given that,
Electric field strength,
We know that,
Charge of electron,
Mass of electron,
From the definition of electric field, ...............(1)
According to Newton's second law, F = ma..........(2)
From equation (1) and (2)
or
So, the horizontal component of acceleration of an electron is .
Hence, it is the required solution.
Answer:
Both of you did the same work but you expended more power.
Explanation:
<em>Work done</em> by an object is calculated by force applied multiplied by the distance.
W=F*d
From the figure given below let us calculate force applied bith you and yopur friend.
Let us take the stairs in positive x direction,
Work done by you W₁ ,
The force applied Fₓ = F - mgsinθ =maₓ
here aₓ = 0, because both of you move with constant speed
F - mgsinθ = 0
F= mgsinθ
The work done by you on the suitcase is
W = F L cos0° , where L is he length of the staircase.
W = FL = mgsinθL , by substituting value of F
Work done by you is W₁ = mgLsinθ
Similarly work done by your friend is W₂ = mgLsinθ.
Because both of you carry suitcase of same weight and in staircase is in same angle the force applied is same .
Therefore <em>work done by both of you is same</em> . Both of you did equal work.
The power , is defined as amount of energy converted or transfered per second or rate at which work is done .
P = =
Power spend by you P₁ = mgLsinθ/t
P₁ = 15*9.8*Lsinθ/30
P₁ = 4.9L sinθ eqn 1
Power spend by your friend is P₂ = mgLsinθ/t
P₂ =15*9.8*Lsinθ/60
P₂ = 2.45Lsinθ eqn 2
Dividing eqn 1 and eqn 2
P₁ = 2P₂
You have spend more power than your friend .
Hence Both of you did equal work but you spend more power.
