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ELEN [110]
4 years ago
11

A 12-V battery maintains an electric potential difference between two parallel metal plates separated by 10 cm. What is the elec

tric field between the plates? a. 1.2 V/m b. 12 V/m c. 120 V/m d. zero
Physics
1 answer:
Sauron [17]4 years ago
4 0

Answer:

The electric field between the plates is 120 V/m.

(c) is correct option.

Explanation:

Given that,

Potential difference = 12 volt

Distance = 10 cm = 0.1 m

We need to calculate the electric field between the plates

Using formula of electric field

E = \dfrac{V}{d}

Where, V = potential difference

d = distance between the plates

Put the formula

E =\dfrac{12}{0.1}

E=120\ V/m

Hence, The electric field between the plates is 120 V/m.

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(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

<h3>Work done by the applied force</h3>

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

<h3>Work done by frictional force</h3>

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

<h3>Net work done by all the forces on the tractor</h3>

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

Learn more about work done here: brainly.com/question/25573309

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The amplitude of a wave tells us about the intensity or brightness of the light relative to other light waves of the same wavelength.
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A metallic sphere of radius 5 cm is charged such that the potential of its surface is 100 V (relative to infinity). Draw the plo
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Answer:

Attached below

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