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goblinko [34]
3 years ago
5

1. How is electric potential energy similar to gravitational potential energy? How is it different? Where will an electron bound

in an atom and have the largest electrical potential energy?
Physics
1 answer:
Korolek [52]3 years ago
7 0
Both ve similar equations 
<span>both are energies of one object w.r.t another </span>
<span>differences- electric pe is due to electrostatic force and gravitational pe is due to gravitational force </span>
<span>electric pe is > than gravitational pe since electrostatic force> gravitational force </span>
<span>electron bound in an atom ll ve largest potential enegy in its ground state. i think hope it helps</span>
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I need help thank you​
Brums [2.3K]

Answer:

D

Explanation:

3 0
3 years ago
Acceleration is measured in_________<br><br><br> m<br><br><br> g<br><br><br> m/s<br><br><br> m/s2
Nana76 [90]
Acceleration is measured in m/s².

Answer: m/s²
4 0
3 years ago
Please help!! (Picture attached)
KonstantinChe [14]
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3 years ago
A 2.5-kg ball and a 5.0-kg ball have an elastic collision. Before the collision, the 2.5-kg ball was at rest and the other ball
lesantik [10]

The kinetic energy of 2.5 kg ball after collision is 27.09 J.

Answer:

Explanation:

In elastic collision, the sum of momentum of the objects before collision will be equal to the sum of momentum of the objects after collision.  

We know that momentum is the product of mass and velocity acting on any object.

So, the conservation of energy in elastic collision leads to following equation:

M_{1} u_{1} +M_{2} u_{2}=M_{1}  v_{1}+M_{2}  v_{2}

Since, the momentum is conserved ,the kinetic energy will also be conserved in elastic collision. So

M_{1} u_{1} ^{2}+M_{2} u_{2} ^{2}=M_{1}v_{1} ^{2}+  M_{2}v_{2} ^{2}

Since initial velocity for M1 ball is zero, then

M_{2} u_{2}=M_{1}  v_{1}+M_{2}  v_{2}

and

M_{2} u_{2} ^{2}=M_{1}v_{1} ^{2}+  M_{2}v_{2} ^{2}

So, on solving all the above equation, we get an equation for velocity and that is

\frac{2M_{2}u_{2} }{(M_{1}+M_{2}  }=final velocity of ball with mass 2.5 kg

v = \frac{2(5*3.5)}{2.5+5}=4.67 m/s

So kinetic energy will be 1/2 mv2

Kinetic energy of 2.5 kg ball is \frac{1}{2}*2.5*(4.67)^{2}  =27.09 J

So the kinetic energy of 2.5 kg ball after collision is 27.09 J.

6 0
3 years ago
The same book is placed on a table .9m high. What type of energy does it have and how much?
Lina20 [59]

<em>mass (m)= 5 kg</em>

<em>height (h)= 9m </em>

<em>gravity (g)= 9.8 m/s^2</em>

It has Potential energy. (PE)

• PE = mgh

Replacing:

PE = 5 * 9.8 * 9 = 441 Joules

6 0
1 year ago
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