The correct answer is
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force per unit charge.
In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
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where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
Answer:
uh finish the question please lol.
Answer:
1.6675×10^-16N
Explanation:
The force of gravity that the space shuttle experiences is expressed as;
g = GM/r²
G is the gravitational constant
M is the mass = 1.0 x 10^5 kg
r is the altitude = 200km = 200,000m
Substitute into the formula
g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²
g = 6.67×10^-6/4×10^10
g = 1.6675×10^{-6-10}
g = 1.6675×10^-16N
Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N
Answer:
10 m/s^2
Explanation:
Equation: F = ma.
a = acceleration
m = mass
F = force
Because we are trying to find acceleration instead of force we want to rearrange the equation to solve for a which is F/m = a.
F = 20
m = 2
a = ?
a = F/m
a = 20/2
a = 10 m/s^2