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Ann [662]
3 years ago
13

−11b+7=40 solve for b

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0

Answer:

<em>B=-3</em>

Step-by-step explanation:

<em>-11b+7=40</em>

<em />

<em>Subtract -7 from both sides</em>

<em />

<em>-11b-7=40-7</em>

<em />

<em>11b=33</em>

<em />

<em>divide by -11</em>

<em />

<em>11b/-11=33/-11</em>

<em />

<em>-11 and -11 cancel out, leaving you with B=-33/11</em>

<em />

thus B=-3

Marizza181 [45]3 years ago
4 0

Answer:

Step-by-step explanation:

subtract 7 on both sides

40-7=33

-11b=33

divide -11 on both sides

b=-3

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X + 8 = 9. Find the value of x.
algol [13]

Answer:

x = 1

Step-by-step explanation:

x + 8 = 9

=> x = 9 - 8

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2 years ago
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A rectangle has a perimeter of 84 miles and a height of 26 miles .what is the length of the base?
ExtremeBDS [4]

Answer:

16 miles

Step-by-step explanation:

The height is 26 miles. Multiply that by 2 which gets 52 and then subtract that from 84. That gives you 32 which means the sum of the lengths is 32/2 which is 16 miles

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3 years ago
Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (
Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

(c) 209 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138    (1)

The second equation in the unknowns is

3B + 5N = 71  (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===>   40B + 30N = 690   (3)

Multiplying (2) by 6 ===>  18B + 30N = 426    (4)

(3) - (4) eliminates the N variables and yields

22B = 264   ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==>  36 + 5N = 71 ==> 5N = 71-36 = 35 ==>  N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

(c) If we add both equations (1) and (2), we get

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

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