the square root is 13.7 hope this helps!
Is this all the problem wants ?
I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].
Answer:
74.0°
Step-by-step explanation:
In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.
Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.
Using sine rule, we can find ∠K:

"The quotient of a number and 3 less than twice the number" would translate to the expression x/(2x-3)
Basically we have x up top the fraction and 2x-3 in the bottom denominator of the fraction. The slash / means divide