Answer:
44 cookies
Step-by-step explanation:
add the remaining cookies to the ones he gave away
(8+14)=22
double that
22x2
answer
44
Answer:
90 students.
Step-by-step explanation:
Given 1/4 of the 120 students took woodshop, just take the 3/4 that didn't take it:

Find common factors between 4 and 120 to simplify, so 4.

Now multiple across to get 90.
Answer:
original is 4 & 6.
for 54 sq inch= 6 & 9 and for 96 sq inch=8 & 12
Step-by-step explanation:
Given: The length is 1.5 times the width.
so the length is, l = 1.5w
----(a)
lw = 24 =1.5w(w)
lw = 54=
1.5w(w)
lw = 96
=1.5w(w)
Further simplifying it,
1.5
=24
1.5
=54
1.5
=96
so,
=
=16
=
36
=
64
taking the square root, we get:
w = 4
w = 6
w = 8
By putting the above values in eq (a), we can find their corresponding lengths:
l = 1.5(4) = 6
l = 1.5(6) = 9
l = 1.5(8) = 12
So a few lengths could be:
(l, w)
(6,4)
(9,6)
(12,8)
Answer:
Step-by-step explanation:
I've enclosed a graph to show you that there is one solution.
-4x + 3y = - 12
<u>- 2x + 3y = - 18</u><em><u> </u></em><em> </em>Subtract
-2x = 6 Divide by - 2
-2x/-2 = 6/-2
x = - 3
- 4x + 3y = - 12
-4(-3) + 3y = - 12
12 + 3y = - 12
3y = - 12 - 12
3y = - 24
3y/3 = - 24/3
y = - 8
Which is exactly what the graph shows.
You can tell immediately that this has 1 or more solutions just by looking at the number in front of x and y in each each equation.
It's always a good idea to graph a question like this one. Desmos is a pretty good tool to use if you don't have a graphing calculator.
The y's are the same so you are 1/2 way home in saying what you did.
The x's are different so that means you have at least 1 solution.
Regardless of the size of the square, half the diagonal is (√2)/2 times the side of the square.
The ratio is (√2)/2.
_____
Consider a square of side length 1. The Pythagorean theorem tells you the diagonal measure (d) is ...
... d² = 1² +1² = 2
... d = √2
The distance from the center of the square to one of its corners (on the circumscribing circle) is then d/2 = (√2)/2. This is the radius of the circle in which our unit square is inscribed.
Since we're only interested in the ratio of the radius to the side length, using a side length of 1 gets us to that ratio directly.