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sweet [91]
2 years ago
12

What is x=7 in slope intercept form Please help

Mathematics
1 answer:
4vir4ik [10]2 years ago
3 0

Answer: x=7 or undefined

Step-by-step explanation:

We can't write x=7 in slope intercept form, since it doesn't have an actual slope or y-intercept. You could put undefined, since the slope is undefined.

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13. What is the positive solution to this equation? 4x2 + 18 x= 162​
MaRussiya [10]

Answer:8.5 is x but there is an extra 1

Step-by-step explanation:18x8.5=153+8=162 with an extra one is 162

3 0
3 years ago
The curve
kherson [118]

Answer:

Point N(4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \sqrt{x - 3}<u />

<u />\displaystyle y' = \frac{1}{2}<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                                   \displaystyle y = (x - 3)^{\frac{1}{2}}
  2. Chain Rule:                                                                                                        \displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]
  3. Basic Power Rule:                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{\frac{1}{2} - 1} \cdot (1 \cdot x^{1 - 1} - 0)
  4. Simplify:                                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}} \cdot 1
  5. Multiply:                                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}}
  6. [Derivative] Rewrite [Exponential Rule - Rewrite]:                                          \displaystyle y' = \frac{1}{2(x - 3)^{\frac{1}{2}}}
  7. [Derivative] Rewrite [Exponential Rule - Root Rewrite]:                                 \displaystyle y' = \frac{1}{2\sqrt{x - 3}}

<u>Step 3: Solve</u>

<em>Find coordinates</em>

<em />

<em>x-coordinate</em>

  1. Substitute in <em>y'</em> [Derivative]:                                                                             \displaystyle \frac{1}{2} = \frac{1}{2\sqrt{x - 3}}
  2. [Multiplication Property of Equality] Multiply 2 on both sides:                      \displaystyle 1 = \frac{1}{\sqrt{x - 3}}
  3. [Multiplication Property of Equality] Multiply √(x - 3) on both sides:            \displaystyle \sqrt{x - 3} = 1
  4. [Equality Property] Square both sides:                                                           \displaystyle x - 3 = 1
  5. [Addition Property of Equality] Add 3 on both sides:                                    \displaystyle x = 4

<em>y-coordinate</em>

  1. Substitute in <em>x</em> [Function]:                                                                                \displaystyle y = \sqrt{4 - 3}
  2. [√Radical] Subtract:                                                                                          \displaystyle y = \sqrt{1}
  3. [√Radical] Evaluate:                                                                                         \displaystyle y = 1

∴ Coordinates of Point N is (4, 1).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

4 0
2 years ago
Megan purchased a new gadget for her technology hobby. She plans to sell it sometime in the future; however, its value depreciat
Dmitrij [34]

The coefficient (m) of the expression represents: C. the monthly depreciation value of the gadget.

<h3>What is depreciation?</h3>

Depreciation can be defined as a process in which the monetary value of a physical asset decreases or falls over a period of time, especially due to wear and tear.

In this scenario, we can infer and logically deduce that the coefficient (m) of the given expression represents the monthly depreciation value of Megan's gadget.

Read more on depreciation here: brainly.com/question/25806993

#SPJ1

5 0
2 years ago
Simplify 6(501) using the distributive property. 3012 3006 2988 3000
ella [17]
 Ok so, I assume this is 6 times 501
     501
   x    6
-------------
   3006

5 x 6 = 30
6 x 0 = 0
6 x 1 = 6


3 0
3 years ago
Read 2 more answers
If SF = 5x + 2, SK = 27, and KF = 3x - 1,<br> find KF.
kondor19780726 [428]

Answer:

KF = 35

Step-by-step explanation:

Since it's a line with K in the middle, we know that the distance SF is the same as SK + KF.

(Start at S, first go to K, then continue to F. You've traveled the same distance as from S to F.)

SF = SK + KF

Let's put in the values we got.

5x + 2 = 27 + (3x -1)

Opening the parenthesis.

5x + 2 = 27 + 3x - 1

5x + 2 = 26 + 3x

Now let's subtract 3x from both sides.

2x + 2 = 26

Now, subtract 2 from both sides.

2x = 24

If we divide by 2...

x = 12

We know that...

KF = 3x -1

Since x is 12, let's put that in.

KF = 3 * 12 - 1 = 36 - 1 = 35

Answer: KF is 35 !

3 0
3 years ago
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