I feel like it the answer is A
Answer:
4(x-7)^2-(x-7)+3 (Assuming t is f)
Step-by-step explanation:
Let s(x)=x-7 and t(x)=4x^2-x+3 .
(t o s)(x)=t(s(x))=t(x-7)
Before I continue this means replace the orginal x in t with x-7.
This will then give you
4(x-7)^2-(x-7)+3
Hi, We know:
Sin(a + b) = 2.Sin(a).Sin(b)
Then,
= 2Sin(a).Cos(b)/Cos(a).Cos(b)
Canceling Cos(b)
= 2Sin(a)/Cos(a)
As Tan(a) = Sin(a)/Cos(a)
Then we will stay:
= 2Tan(a)
Or
= Tan(a) + Tan(a)
There is anything wrong on the alternatives
