Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
Answer:
x=3
Step-by-step explanation:
(x−3)^2=0
Set the x−3 equal to 0.
x−3=0
Add 3 to both sides of the equation.
x=3
Answer:
Step-by-step explanation:
Permutation is the ways in which a fixed group or members that can be arranged or ordered and combinations are used when a smaller group has to be chosen from a larger group.
Examples:
<u>Permutation: </u>How many unique combinations of the word MAHNOOR can be formed when the letters will be scrambled
2. In what order or arrangements five people can be seated in the front row?
The number of people are fixed, we have to find the order.
<u>Combination:</u> Choosing two cards from a deck of 52 cards. We are choosing a small group from a larger group of all cards.
2. Choosing 4 students from a class to take part in the competition.
The selection can be made in multiple ways ..
The equation is 76*120/3.
76*120/3
9,120/3
3,040
The car will travel 3,040 yards in 120 seconds at that speed.
well, 26+6 is 32, so divide that by 3 and you'd get 10.67, making daniel 32 by that time and his son being 10 years old
its simple math really, also, i hope this helps you ^-^