Can sm plz help and explain how to do this?

Mathematics

2 answers:

serg [7]4 years ago

8 0

Idk idk idk idk idk idk

zhannawk [14.2K]4 years ago

7 0

Ok. This is how you solve this problem. First you add 42+11 and that equals 53. Then you have 42 paper clips for Crystal and 53 for Gayle. So that is how many paper clips they have each. I hope this helps. .

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According to data from the state blood program, 40 percent of all individuals have group A blood. If six individuals give blood,

Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

$X\sim Bin(n=6, p=0.40)$

Formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

$P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648$

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0

4 years ago

Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4

lana66690 [7]

$\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}$