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Zinaida [17]
4 years ago
14

68 miles to 42.5 miles

Mathematics
2 answers:
Rudiy274 years ago
8 0
42.5/68
=0.625x100
=62.5%
But idk if you meant percent change

hammer [34]4 years ago
3 0
Hello there,
Could you please be more specific.
But what I can understand:
1) Difference
68miles - 42.5miles = 25.5miles
2) Percentage
(42.5miles / 68miles) x 100 % = 62.5 %

Hope this helps :))

~Top
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Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation option
denis-greek [22]

Answer:

The probability that he teleports at least once a day =  \mathbf{\frac{5}{9}}

Step-by-step explanation:

Given -

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.

Total no of outcomes = 3

P( He not choose teleport in the morning ) = \frac{2}{3}

P( He not choose teleport in the evening ) = \frac{2}{3}

P ( he choose teleports at least once a day ) = 1 - P ( he not  choose teleports in a day )

                                                         = 1 - P( He not choose teleport in the morning ) \times P( He not choose teleport in the evening )

                                          =  1 - \frac{2}{3}\times\frac{2}{3}

                                           =  \frac{5}{9}

3 0
3 years ago
Suppose that a ball is dropped from the upper observation deck of the CN Tower in Toronto, 450 m above the ground. Find the velo
mr Goodwill [35]

Answer:

1350

Step-by-step explanation:

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7 0
3 years ago
Experimentally verify sum of three angles of an triangle is 180⁰.​
svetlana [45]

Draw line a through points A and B. Draw line b through point C and parallel to line a.

Since lines a and b are parallel, <)BAC = <)B'CA and <)ABC = <)BCA'.

It is obvious that <)B'CA + <)ACB + <)BCA' = 180 degrees.

Thus <)ABC + <)BCA + <)CAB = 180 degrees.

Lemma

If ABCD is a quadrilateral and <)CAB = <)DCA then AB and DC are parallel.

Proof

Assume to the contrary that AB and DC are not parallel.

Draw a line trough A and B and draw a line trough D and C.

These lines are not parallel so they cross at one point. Call this point E.

Notice that <)AEC is greater than 0.

Since <)CAB = <)DCA, <)CAE + <)ACE = 180 degrees.

Hence <)AEC + <)CAE + <)ACE is greater than 180 degrees.

Contradiction. This completes the proof.

Definition

Two Triangles ABC and A'B'C' are congruent if and only if

|AB| = |A'B'|, |AC| = |A'C'|, |BC| = |B'C'| and,

<)ABC = <)A'B'C', <)BCA = <)B'C'A', <)CAB = <)C'A'B'.

4 0
3 years ago
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5 0
3 years ago
If x = 12 and y = 3, what is the value of the following expression?
Natasha_Volkova [10]

Answer:

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I hope this helps

6 0
2 years ago
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