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Elis [28]
3 years ago
13

Write an irrational number that can be added to the irrational number square root of 20 to get a rational sum of 11 .

Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

  11 -√20

Step-by-step explanation:

If you want ...

  √20 + x = 11

You can find x by subtracting √20 from both sides of the equation:

  x = 11 -√20

The number you're looking for is 11 -√20.

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X²+x-12
Dovator [93]

Answer:

x+3

Step-by-step explanation:

just divide! im not sure if this you want an expression or a simplified expression.

3 0
3 years ago
A box contains 12 cereal bars. The empty box weighs
Vesna [10]

Answer:

1.4oz

Step-by-step explanation:

You subtract the weight of the box and the bars with the empty box. Then divide the answer you got from that, with 12 and you get your answer.

4 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply. 3^x A. 3 • 3^x + 1 B. 3 • 3^x - 1 C.18^x/3 D.(18/6)^x E
inn [45]

Answer:

<h2>B, D, F</h2>

Step-by-step explanation:

Use\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{b^n}=\left(\dfrac{a}{b}\right)^n\\=================\\A.\ 3^{x+1}=3^x\cdot 3\neq3^x\\\\B.\ 3\cdot3^{x-1}=3\cdot3^x\cdot3^{-1}=(3^1\cdot3^{-1})\cdot3^x=3^{1+(-1)}\cdot3^x=3^0\cdot3^x=1\cdot3^x=3^x\\\\C.\ \dfrac{18^x}{3}\neq3^x\\\\D.\ \left(\dfrac{18}{6}\right)^x=(3)^x=3^x\\\\E.\ x^3\neq3^x\\\\F.\ \dfrac{18^x}{6^x}=\left(\dfrac{18}{6}\right)^x=(3)^x=3^x

8 0
3 years ago
Please HELp <br> How do u solve dis.
exis [7]

Step-by-step explanation:

x+77=126 (vertical opposite angles are equal)

x=126-77

x= 49

4 0
4 years ago
Given that f(x) = x2 - 2x - 15,
Gala2k [10]

a) (0; -15)

you just let x be equal to 0.

b) ( -5; 0) and (3;0)

you just let y/ f(x) equal to 0.

c)

3 0
3 years ago
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