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Elina [12.6K]
2 years ago
15

5/6 but if i mulsiply by 4 it gives me whole diff

Mathematics
1 answer:
miskamm [114]2 years ago
4 0

Answer:

3.33 or 3 1/3

Step-by-step explanation:

You're correct to multiply by 4.

Your answer will be 10/3

Just make it a mixed number: 3 1/3

3.33 is 10/3 as a decimal.

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7 days 8 hours 20 minutes
Citrus2011 [14]
The Answer is F.

20min - 30min is -10 so you can take it out of 8h which will leave you with 7h and 50 minutes then
7h and 50 min minus 10 h is -3 h and 50 minutes take it out of the 7 day’s which leaves you with 6days and 24 h minus 3 h that it 6days and 21 h and 50 minutes in total and minus the ram aiming 4 days which will be

2days 21 hours 50 minutes and that gives you the answer F
7 0
3 years ago
The diameter of a circle is 4 centimeters,what is the area of that circle
avanturin [10]
Area of circle = πr² 

Area of circle = π(4÷2)² = 12.57 cm²
4 0
3 years ago
Every day, a group of 9 workers picks pea pods in a field. Each worker picks 240 pea pods, and each pea pod contains 6 peas.
Marrrta [24]

9(240)= 2160 pea pods picked per day

2160(6)=12960 peas picked per day

Answer: The workers pick 12,960 peas every day

3 0
3 years ago
Read 2 more answers
Find the product of 51 and -2.5. Use the distributive property to rewrite and solve. The first step is done for you. 51(-2.0) +
I am Lyosha [343]

Answer:

-12.75

Step-by-step explanation:

Find the product of 51 and -2.5. Use the distributive property to rewrite and solve.

The next step using Distributive property is to expand the brackets

5.1 × 2.5

Step 1: Distributive property

51(-2.0) + 51(-0.5)

Step 2: Expand the brackets

-10.2 + -2.55

Step 3

- 12.75

4 0
3 years ago
Read 2 more answers
OOOO
lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

x^4+95x^2 -500=0

Substituting x^2=a, given bi-quadratic equation reduces in the form of following quadratic equation:

a^2 +95a -500=0\\

Let us factorize the above quadratic equation:

a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\

Since square root of a negative number cannot be found, so:

x \neq \pm \sqrt{-100}\\

CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\

3 0
3 years ago
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