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algol13
3 years ago
11

What are types of legislature

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

Two common types of legislature are those in which the executive and the legislative branches are clearly separated, as in the U.S. Congress, and those in which members of the executive branch are chosen from the legislative membership, as in the British Parliament.

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−2/3(3x−4)+3x=5/6 whoever gets right gets brainlyest
REY [17]

−2/3(3x−4)+3x=5/6

= -11/6

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Fourth roots of 256 help me
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Fourth root of 256 is ±4.

hope this helps

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What is a21 of the arithmetic sequence for which a7=−19 and a10=−28? A. -35 B. 35 C. -58 D. -61
shepuryov [24]

Answer:

a21 = -61

Step-by-step explanation:

a_{n}=a_{1}+(n-1)d

-19=a_{1}+(7-1)d

-28=a_{1}+(10-1)d (subtract to eliminate a₁)

9 = -3d

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= -61

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3 years ago
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Express 17/5 as a mixed number, what is the answer?​
pychu [463]

Answer:

Step-by-step explanation:

3 2/5

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The phenomenon of bottle flipping has hit the nation. You design a machine that can randomly flip a bottle. You observe 2180 ran
krek1111 [17]

Answer:

The variable of interest is the proportion of flips that land the correct way when flipped randomly.

The necessary conditions n\pi \geq 10 and n(1-\pi) \geq 10 are present.

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

Step-by-step explanation:

Variable of Interest:

Proportion of flips that land the correct way when flipped randomly.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Necessary conditions:

The necessary conditions are:

n\pi \geq 10

n(1-\pi) \geq 10

You observe 2180 random, independent flips, and 325 land the correct way.

This means that n = 2180, \pi = \frac{325}{2180} = 0.149

Necessary conditions

n\pi = 2180*0.149 = 325 \geq 10

n(1-\pi) = 2180*0.851 = 1855 \geq 10

The necessary conditions n\pi \geq 10 and n(1-\pi) \geq 10 are present.

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.33.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.131

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 + 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.167

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

8 0
3 years ago
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