Answer:its a nice
Step-by-step explanation:
It could be
Answer: ill try looking this one up to help u just add me on snap its johni_spurgeon
Step-by-step explanation:
Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
K- (-8, -2)
L- (2, -2)
J- (-8, -5)
M- (2, -5)
Step-by-step explanation:
Vertices refer to the points where the lines connect, or corners. In this problem they're represented by K, L, J, and M.
The current coordinates are-
K- (-8, -4)
L- (2, -4)
J- (-8, -7)
M- (2, -7)
Since the Y coordinate refers to vertical distance and the X coordinate refers to horizontal distance, translating them two units up would involve adding positive two to each y coordinate.
Therefore the new coordinates would be
K- (-8, -2)
L- (2, -2)
J- (-8, -5)
M- (2, -5)
Hope this was helpful! Sorry if I messed up askdjasjk
Answer:
y=3-2x
Step-by-step explanation:
Move all terms that don't contain y to the right and solve.
