

Extrema can occur when the derivative is zero or undefined.

Maxima occur where the first derivative is zero and the second derivative is negative; minima where the second derivative is positive. You have

At the critical points, you get


So you have a minimum at

and a maximum at

.
Meanwhile, as

, it's clear that

, so these extrema are absolute on the function's domain.
It is true, they are congruent by doing a proof. You have to divide the trapezoid into 2 equal triangles. Then you can prove it. They are congruent since corresponding parts of congruent triangles are congruent.
Answer <u>(assuming it can be in slope-intercept form)</u>:
Step-by-step explanation:
1) First, find the slope of the line between the two points by using the slope formula,
. Substitute the x and y values of the given points into the formula and solve:
Thus, the slope of the line is
.
2) Next, use the point-slope formula
to write the equation of the line in point-slope form. Substitute values for
,
, and
in the formula.
Since
represents the slope, substitute
in its place. Since
and
represent the x and y values of one point the line intersects, choose any of the given points (it doesn't matter which one, it will equal the same thing) and substitute its x and y values into the formula as well. (I chose (-2,0), as seen below.) Then, isolate y and expand the right side in the resulting equation to find the equation of the line in slope-intercept form:
