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3 years ago

7

The word "nitrogen" could stand for a(n)

1 answer:

Gala2k [10]3 years ago

8 0

A. atom.

B. element.

C. molecule

Answer: D. All of these could describe nitrogen.

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If a train travels 500 kilometers from Stockholm to

o-na [289]

Hello,

Average speed is total distance divided by total time. From the problem, our total distance is given as 500 kilometers and given time is 5 hours. Therefore, the average speed is:

$\displaystyle{v_\text{average}=\sum_{i=1}^n \dfrac{s_i}{t_i}}\\\\\displaystyle{v=\dfrac{500\ \text{km}}{5 \ \text{h}}}\\\\\displaystyle{v=100 \ \text{km/h}}$

Therefore, the average speed is 100 km/h. Please let me know if you have any questions!

4 0

1 year ago

100 POINTS!!! :D

charle [14.2K]

Explanation:

... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

4 0

3 years ago

Read 2 more answers

The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins

krek1111 [17]

Answer:

Temperature, T = 1542.10 K

Explanation:

It is given that,

The black body radiation emitted from a furnace peaks at a wavelength of, $\lambda=1.9\times 10^{-6}\ m$

We need to find the temperature inside the furnace. The relationship between the temperature and the wavelength is given by Wein's law i.e.

$\lambda\propto \dfrac{1}{T}$

or

$\lambda=\dfrac{b}{T}$

b = Wein's displacement constant

$\lambda=\dfrac{2.93\times 10^{-3}}{T}$

$T=\dfrac{2.93\times 10^{-3}}{\lambda}$

$T=\dfrac{2.93\times 10^{-3}}{1.9\times 10^{-6}\ m}$

T = 1542.10 K

So, the temperature inside the furnace is 1542.10 K. Hence, this is the required solution.

3 0

3 years ago

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

3 0

3 years ago

A 4,000 kg boat floats with one-third of its volume submerged. if two more people get into the boat, each of whom weighs 690 n,

AveGali [126]

The weightiness of the added water displaced is equivalent to the joined weight of the two extra people who come to be into the boat:

<span>m water g = 2 x 690 N</span>

<span> = 1,380 N</span>

<span>
</span>

The mass of the water displace is then

<span>m water g = 1,380 N</span>

<span> = 1,380 N / 9.8 m/s^2</span>

<span> = 141 kg</span>

<span>
</span>

Compute the calculation for density for the volume of water displace and practice this outcome for the mass of the water displace to get the answer:

<span>p water = mass of water / volume of water</span>

<span>
</span>

<span>volume of water = mass of water / p water</span>

<span> = 141 kg / 1000 kg /m^3 eliminate kilogram</span>

<span> = 0.14 m^3 the additional volume of water that is displaced</span>

4 0

3 years ago